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love history [14]
3 years ago
6

Elmer sees a flying saucer. The radius of the flying saucer is 17 feet. What is the area of the flying saucer (use 3.14 for pi a

nd round to nearest tenth)
Mathematics
1 answer:
sergiy2304 [10]3 years ago
8 0

Answer:

Area of the flying saucer = 907.46 ft^2

Step-by-step explanation:

The Flying saucer is in the shape of a circle.

Radius= 17 feet

Area of the circular flying saucer= \pi *r*r

                                                                         :\pi =\frac{22}{7} =3.14

                                  Area= 3.14*17*17

                                     

  Area of the flying saucer =3.14*289\\\\    =907.46 ft^2

So, the area of the flying saucer is 907.46 ft^2

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What is the area of this triangle ?
oee [108]

Answer:

Area of triangle is 9.88 units^2

Step-by-step explanation:

We need to find the area of triangle

Given E(5,1), F(0,4), D(0,8)

We will use formula:

Area\,\,of\,\,triangle =\sqrt{s(s-a)(s-b)s-c)} \\where\,\, s = \frac{a+b+c}{2}

We need to find the lengths of side DE, EF and FD

Length of side DE = a = \sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2}

Length of side DE = a = =\sqrt{(5-0)^2+(1-8)^2}\\=\sqrt{(5)^2+(-7)^2}\\=\sqrt{25+49}\\=\sqrt{74}\\=8.60

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Length of side EF = b = =\sqrt{(0-5)^2+(4-1)^2}\\=\sqrt{(-5)^2+(3)^2}\\=\sqrt{25+9}\\=\sqrt{34}\\=5.8

Length of side FD = c = \sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2}

Length of side FD = c = =\sqrt{(0-0)^2+(8-4)^2}\\=\sqrt{(0)^2+(4)^2}\\=\sqrt{0+16}\\=\sqrt{16}\\=4

so, a= 8.60, b= 5.8 and c = 4

s = a+b+c/2

s= 8.6+5.8+4/2

s= 9.2

Area of triangle==\sqrt{s(s-a)(s-b)s-c)}\\=\sqrt{9.2(9.2-8.6)(9.2-5.8)(9.2-4)}\\=\sqrt{9.2(0.6)(3.4)(5.2)}\\=\sqrt{97.5936}\\=9.88

So, area of triangle is 9.88 units^2

4 0
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75% of what number is 66?​
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Divide the k own number by the percentage:

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