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Ugo [173]
3 years ago
13

a pyramid has a square base that measures 500 yards by 500 yards, and the pyramid stands 300 yards tall. what is the volume of t

he pyramid?
Mathematics
1 answer:
Alla [95]3 years ago
3 0
<span>Pyramid Volume = (Area of the Base * Height) ÷ 3
</span>
<span>Pyramid Volume = (500 * 500 * 300) / 3
</span>
Pyramid Volume = <span> <span> <span> 25,000,000 </span> </span> </span> cubic yards

Source:
http://www.1728.org/volpyrmd.htm


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can someone pls help me? i have no idea what to do. pls show the work steps for the questions. i will mark u as
tiny-mole [99]

Ok, so the question is based on geometric progression. Remember, the formula for calculating the nth-term of a geometric progression is: a*r^{n-1}. The a in the expression stands for the 1st term of the sequence, and r is the common ratio of the elements of the sequence. Now let's take a look at the problem.

"A ping pong ball has a 75% rebound ration". We can infer that our common ratio, r, is 75% which is 0.75.

"When you drop it from a height of k feet...", this means the first height you drop it from, a.k.a, the first term.

Now going back to the expression, the nth-term = a*r^{n-1}, we can substitute our common ration, 0.75 with r, and our 1st term, k, with a. This becomes: k * 0.75^{n-1}. This becomes our expression.

a. The highest height achieved by the ball after six bounces. Our nth-term here is 6, so let's use our expression to find the 6th term. n_{6} = 235 * 0.75^{6-1} = 235*0.75^{5} = 235*0.2373 = 55.7655ft

b. The total distance travelled by the ball when it strikes the ground for the 12th time. This involves the use of the sum of elements in the geometric progression. The formula for that is \frac{a(1 - r^{n})}{1-r}, provided that r is less than 1, which it is in this case, since 0.75 is less than one. Our nth-term here is 12, so we substitute.

\frac{235(1-0.75^{12})}{(1-0.75)} = 910.2242ft

6 0
2 years ago
14x+2y=-10<br> solve equations for y
Ne4ueva [31]

Answer:

y = -7x - 5

Step-by-step explanation:

14x + 2y = -10

2y = -14x - 10

2y/2 = -14x/2 - 10/2

y = -7x - 5

Hope this helps -w-

3 0
3 years ago
Read 2 more answers
How do you complete the square to rewrite y= x^ -6x + 15 in vertex form
Vaselesa [24]
Vertex form of a quadratic equation is y=a(x-h)^{2}+k
where (h, k) is the vertex. 

Our aim is to write the expression y=x^{2} -6x+15 in the form 
y=a(x-h)^{2}+k



y=x^{2} -6x+15

y=x^{2} -2*3*x+15

y=(x^{2} -2*3*x+ 3^{2})-3^{2}+ 15

y=(x-3)^{2}-9+15

y=(x-3)^{2}+6
5 0
3 years ago
What is thisssssssss plssssssss
RSB [31]

Answer:

I think u should do 2.5 ÷n=r

6 0
3 years ago
How to work it out logically? Question a !!!
Arturiano [62]

Answer:

Fencing is done along KL which is (1500+520.8=2020.8 m) from the top left corner and divides the property into half.

Step-by-step explanation:

Given the figure with dimensions. we have to find the area of given figure.

Area of figure=ar(1)+ar(2)+ar(3)

Area of region 1 = ar(ANGI)+ar(AIB)

                          =L\times B+\frac{1}{2}\times base\times height\\\\=[1500\times (5000-2000-1500)]+\frac{1}{2}\times (3000-1500)\times (5000-2000-1500)\\\\=3375000m^2=337.5ha

Area of region 2 = ar(DHBC)

                       =2000\times1500\\\\=3000000m^2=300ha

Area of region 3 = ar(GFEH)

                             (2000+1500)\times 1000\\\\=3500000m^2=350ha

Hence, Area of figure=ar(1)+ar(2)+ar(3)=337.5ha+300ha+350ha

                                                 =987.5 ha

Now, we have to do straight-line fencing such that area become half and cost of fencing is minimum.

Let the fencing be done through x m downward from B which divides the two into equal area.

⇒ Area of upper part above fencing=Area of lower part below fencing

⇒ar(ANGB)+ar(GKLB)=ar(KLCM)+ar(MDCF)\\\\337500+3000x=(3500-x)\times 1000+2000(1500-x)\\\\3375000+3000x=3500000-1000x+3000000-2000x\\\\6000x=315000\\\\x=\frac{315000}{6000}=520.8m

Hence, fencing is done along KL which is (1500+520.8=2020.8 m) from the top left corner and divides the property into half.

7 0
3 years ago
Read 2 more answers
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