Answer:
B. 1/6^9
Step-by-step explanation:
6^-2 = 1/6^2
1/6^2 * 6^5 = 6^5/6^2 = 6^3
6^(3 * -3) = 6^-9= 1/6^9
Answer:
$6.03
Step-by-step explanation:
The question is asking us how much each pair of socks cost. With the information we are given, we know that there are 5 pairs and that they all cost the same amount. If the total were just the 5 socks, we could easily divide the total by 5 to get the price of each pair but that's not the case. The soccer ball is included in the final cost. To overcome this, we just have to subtract the soccer ball's cost ($45) from the total.
So we subtract $45 from $75.15, giving us $30.15, the total amount of all the socks. However we need to find out how much each pair costs and there are 5 of them, so we divide 30.15 by 5. This gives us the answer, $6.03.
Each pair of socks cost $6.03.
Simpler Explanation:
- $75.15 - $45 = $30.15
- $30.15 / 5 = $6.03
The answer is $6.03
Answer:
4a^2 - 15b + 9b^2
Step by step explanation:
First picture)
I: 5x+2y=-4
II: -3x+2y=12
add I+(-1*II):
5x+2y-(-3x+2y)=-4-12
8x=-16
x=-2
insert x=-2 into I:
5*(-2)+2y=-4
-10+2y=-4
2y=6
y=3
(-2,3)
question 6)
I: totalcost=115=3*childs+5*adults
II: 33=adults+childs
33-adults=childs
insert childs into I:
115=3*(33-adults)+5*adults
115=99-3*adults+5*adults
16=2*adults
8=adults
insert adults into II:
33-8=childs
25=childs
so it's the last option
question 7)
a) y<6 and y>2 can also be written as 2<y<6, so solution 3 exist for example
b) y>6 and y>2 can also be written as 2<6<y, so solution 7 exist for example
c) y<6 and y<2 inverse of b: y<2<6, so for example 1
d) y>6 and y<2: y<2<6<y, this is impossible as y can be only either bigger or smaller than 2 or 6
so it's the last option
question 8)
I: x+y=12
II: x-y=6
subtract: I-II:
x+y-(x-y)=12-6
2y=6
y=3
insert y into I:
x+3=12
x=9
(9,3)
question 9)
I: x+y=6
II: x=y+5
if you take the x=y+5 definition of II and substitute it into I:
(y+5)+y=6
which is the second option :)
