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Vesna [10]
4 years ago
14

ALGEBRA HELP PLEASE

Mathematics
1 answer:
IrinaVladis [17]4 years ago
4 0
Start by solving for x in the first problem:
3x=3+9y
x=1+3y
Then plug that into the second equation:
6(1+3y)-3y=-24
6+18y-3y=-24
15y=-30
y=-2
Then plug that back into first equation:
3x-9(-2)=3
3x+18=3
3x=-15
x=-5 
Then I would check your answer by plugging those into both equations:
3(-5)-9(-2)=3
-15+18=3
3=3 CHECK
6(-5)-3(-2)=-24
-30+6=-24
-24=-24 CHECK
 
So the answer is x=-5 y=-2

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The answer is (22.5,-12.5)

Hope this helps!
4 0
3 years ago
Can you please help me out with a question
Finger [1]

The standard equation of a circle is expressed as

(x - h)^2 + (y - k)^2 = r^2

where

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From the graph,

h = - 1

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By substituting these values into the equation, we have

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8 0
2 years ago
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6 0
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3 years ago
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nexus9112 [7]

Answer:

Step-by-step explanation:

2x + 3y = 2

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substitute the value of x

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6 0
3 years ago
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