Answer:
JL = 52
Step-by-step explanation:
It is given in the question that K is the midpoint of JL.
So, JK = KL ......... (1)
Now, given that, JK =3x - 1 and KL = 2x + 8
Therefore, from equation (1), we can write
3x - 1 = 2x + 8
⇒ x = 9
So, JK = 3x - 1 = 3(9) -1 = 26 and KL = 2x + 8 = 2(9) + 8 = 26
Hence, JL = JK + KL = 26 + 26 = 52. (Answer)
Answer:12
Step-by-step explanation:
4 by 3
so 4x3=12
Answer:
33/12 if simplified 2 3/4
Step-by-step explanation:
Answer:
can you help me on myquestio
Step-by-step explanation:
Answer:
Y' = -xsin(2x) + 2cos(2x)
Step-by-step explanation:
For this problem, we will need to use the product rule since you have two terms that contain the variable x.
The product rule is simply as follows:
The derivative of the function is the product of the first term times the derivative of the second term plus the derivative of the first term times the second term.
Note the derivative of 2x with respect to x, is 2.
Note the derivative of cos(2x) with respect to x is (-1/2) sin(2x).
With this in mind, let's find the derivative of our function with respect to x.
Y = 2xcos2x
Y = 2x * cos(2x)
Y' = 2x * (-1/2)sin(2x) + 2 * cos(2x)
Y' = (2x * -1 / 2) sin(2x) + 2 * cos(2x)
Y' = (-x)sin(2x) + 2cos(2x)
So the derivative of our function is Y' = -xsin(2x) + 2cos(2x) according to the application of the product rule.
Cheers.
