Divide.

Mathematics

1 answer:

chubhunter [2.5K]3 years ago

3 0

I would think it is b sorry if im wrong

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The floor of Cara's living room is 10 feet by 14 feet. What is the area, in square feet, of the largest circular rug that can fi

Rus_ich [418]

Answer:

$78.5\ ft^{2}$

Step-by-step explanation:

we know that

If the floor of Cara's living room is 10 feet by 14 feet

then

the diameter of the larger circular rug that can fit in Cara's living room is equal to 10 feet

<em>Find the area of the circular rug</em>

The area of the circle is equal to

$A=\pi r^{2}$

we have

$r=10/2=5\ ft$ ----> the radius is half the diameter

$\pi=3.14$

substitute the values

$A=(3.14)(5)^{2}=78.5\ ft^{2}$

3 0

3 years ago

Find the x- and y- intercepts of parabola y=5x^2-16x+10

____ [38]

Y-INTERCEPT

$y = 5x^2 - 16x + 10$

The y-intercept is where the equation/curve/parabola cosses the y-axis.

The y-axis is where x = 0. (The x-axis is where y = 0)

To find the y-intercept:

$\text{y-axis} \rightarrow \text{x = 0} \rightarrow y = 5(0)^2 -16(0) + 10 = 10$

The y-intercept must be at (0, 10)

X-INTERCEPT (ROOTS/SOLUTIONS)

$y = 5x^2 - 16x + 10\\\text{make it equal 0}\\y = 0\\\therefore 5x^2 - 16x + 10 = 0$

We need to use the quadratic formula

The quadratic formula helps us find what values of $x$ make the equation = 0

Quadratic formula: $x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$

$x=\frac{-(-16) + \sqrt{(-16)^2-4(5)(10)}}{2(5)}\\\\x = \frac{16 + \sqrt{256-200}}{10}\\x = \frac{16 + \sqrt{56}}{10}\\x = \frac{16 + 2\sqrt{14}}{10}\\x = \frac{8 + \sqrt{14}}{5}\\\\\\x=\frac{-(-16) - \sqrt{(-16)^2-4(5)(10)}}{2(5)}\\\text{doing the same thing...}\\\text{end up with...}\\x = \frac{8 - \sqrt{14}}{5}\\$