log_10 (600) is between 2 and 3
2,77815
Answer:102.22
Step-by-step explanation:
Answer:
The cost of 1kg jam is $7 and the cost of 1kg butter is $4
Step-by-step explanation:
Let jam = x
butter = y
3x + 2y = 29 -----(1)
6x + 3y = 54 -----(2)
(1)×2 ->
6x + 4y = 58 -----(3)
(3)-(2) ->
y = 4
suby=4into(2)
6x + 3(4) = 54
6x = 42
x = 7
(Correct me if i am wrong)
X< -2 means that x must be smaller than -2, so something like -3, -4, -5, etc
The only solution set that fits this is A.
(p² + 3p + 6) + (2p² + 6p + 6)
First you must combine (aka sum) like terms. Like terms are numbers that have matching variables OR are numbers with out variables OR have matching variables with matching exponents. In this case the like terms are p² and 2p² (they both have the exponent p that is squared); 3p and 6p (they both have the variable p attached); and 6 and 6 (both numbers without variables)
(p² + 2p²) + (3p + 6p) + (6 + 6)
3p² + 9p + 12
Hope this helped!
~Just a girl in love with Shawn Mendes
