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juin [17]
3 years ago
8

The one world trade center In New york City is about 3 1/5 times as tall as the Washington Monument In Washington D.C THE Washin

gton Monument is 555 feet tall. About how tall is the one world trade center?
Mathematics
2 answers:
Naya [18.7K]3 years ago
5 0
So you would do 555 times 3 1/5. Your answer would be 1776 feet tall.
serg [7]3 years ago
3 0

Answer:

1776 feet

Step-by-step explanation:

Given: The one world trade center In New york City is about 3\frac{1}{5} times as tall as the Washington Monument In Washington D.C The Washington Monument is 555 feet tall.

To Find: how tall is the one world trade center

Solution:

Height of The Washington Monument  =555 \text{feet}

Let height of world trade center In New york be =\text{x}

Now,

one world trade center In New york City is about 3\frac{1}{5} times as tall as the Washington Monument In Washington D.C

therefore

               \text{height of world trade center}=\frac{16}{5}\times\text{height of The washington monument}

now on putting value

                \text{x}=\frac{16}{5}\times555

                \text{x}=1776 \text{feet}

Hence the height of world trade center in New York is 1776 \text{feet}

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A fence must be built to enclose a rectangular area of 20,000 ft^2. Fencing material costs $4 per foot for the two sides facing
Marysya12 [62]

The cost of the least expensive fence is $3200

Step-by-step explanation:

The given is:

  • A fence must be built to enclose a rectangular area of 20,000 ft²
  • Fencing material costs $4 per foot for the two sides facing north and south and ​$8 per foot for the other two sides

We need to find the cost of the least expensive fence

Assume that the length of each side opposite to North or South is x feet and the length of each other sides  is y feet

∵ The length of the rectangle = x feet

∵ The width of the rectangle = y feet

∵ The rectangular area is 20,000 ft²

- Area of a rectangle = length × width

∴ x × y = 20,000

- Divide both sides by x to find y in terms of x

∴ y=\frac{20,000}{x}

The fence's length is equal to the perimeter of the rectangular area

∵ Perimeter of the rectangle = 2 length + 2 width

∴ Perimeter of the rectangle = 2x + 2y

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∴ x costs $4 per foot

∵ The cost of the other two sides is $8 per foot

∴ y costs $8 per feet

The cost of the fence is the sum of the products of 4 , 2x and 8 , 2y

∵ The cost of the fence (C) = 4(2x) + 8(2y)

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∴ C=8x+\frac{320,000}{x}

To find the least expensive differentiate C with respect to x and equate the answer by 0 to find the value of x

∵ \frac{320,000}{x} can be written as 320,000x^{-1}

∴ C=8x+320,000x^{-1}

∵ \frac{dC}{dx}=8(1)x^{1-1}+320,000(-1)x^{-1-1}

∴ \frac{dC}{dx}=8-320,000x^{-2}

- Equate \frac{dC}{dx} by zero

∴ 8-320,000x^{-2}=0

∵ -320,000x^{-2}=-\frac{320,000}{x^{2}}

∴ 8-\frac{320,000}{x^{2}}=0

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Substitute x in the equation of C to find the least cost of fence

∵ C=8(200)+\frac{320,000}{(200)}

∴ C = 1600 + 1600

∴ C = 3200

The cost of the least expensive fence is $3200

Learn more:

You can learn more about the differentiation in brainly.com/question/4279146

#LearnwithBrainly

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