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3 years ago

Hello chaps, please help me with this absurb eqution, "I think of a number add one then double the result

Mathematics

1 answer:

ziro4ka [17]3 years ago

6 0

Answer:

2n+2

Step-by-step explanation:

Let the number = n.

Add 1 to n:

n+1

Double n+1:

2(n+1)

Distribute:

2n+2

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With bases V1, V2 , V3 andw1, w2 , W3, suppose T(v1) = w2 and T(v2) = T(v3) = w1 + w3 . T is a linear transformation. Find the m

Roman55 [17]

Answer:

See picture and explanation below.

Step-by-step explanation:

With this information, the matrix A that you can find is the transformation matrix of T. The matrix A is useful because T(x)=Av for all v in the domain of T.

A is defined as $T=([T(v_1)] [T(v_2] [T(v_3)])\text{ where }[T(v_i)]$ denotes the vector of coordinates of $T(v_i)$ respect to the basis (we can apply this definition because forms a basis for the domain of T).

The vector of coordinates can be computed in the following way: if $T(v_i)=a_1w_1+a_2w_2+a_3w_3$ then $[T(v_i)]=(a_1,a_2,a_3)^t$ .

Note that we have all the required information: $T(v_1)=0w_1+1\cdot w_2+0w_3$ then $[T(v_1)]=(0,1,0)^t$

$T(v_2)=T(v_3)=1\cdot w_1+0w_2+0w_3$ hence $[T(v_2)]=[T(v_3)]=(1,0,0)^t$

The matrix A is on the picture attached, with the multiplication A(1,1,1).

Finally, to obtain the output required at the end, use the properties of a linear transformation and the outputs given:

$T(v_1+v_2+v_3)=T(v_1)+T(v_2)+T(v_3)=w_2+w_1+w_1=w_2+2w_1$

In this last case, we can either use the linearity of T or multiply by A.

4 0

3 years ago

Examine the following steps. Which do you think you might use to prove the identity Tangent (x) = StartFraction tangent (x) + ta

Over [174]

Answer:

The correct options are;

1) Write tan(x + y) as sin(x + y) over cos(x + y)

2) Use the sum identity for sine to rewrite the numerator

3) Use the sum identity for cosine to rewrite the denominator

4) Divide both the numerator and denominator by cos(x)·cos(y)

5) Simplify fractions by dividing out common factors or using the tangent quotient identity

Step-by-step explanation:

Given that the required identity is Tangent (x + y) = (tangent (x) + tangent (y))/(1 - tangent(x) × tangent (y)), we have;

tan(x + y) = sin(x + y)/(cos(x + y))

sin(x + y)/(cos(x + y)) = (Sin(x)·cos(y) + cos(x)·sin(y))/(cos(x)·cos(y) - sin(x)·sin(y))

(Sin(x)·cos(y) + cos(x)·sin(y))/(cos(x)·cos(y) - sin(x)·sin(y)) = (Sin(x)·cos(y) + cos(x)·sin(y))/(cos(x)·cos(y))/(cos(x)·cos(y) - sin(x)·sin(y))/(cos(x)·cos(y))

(Sin(x)·cos(y) + cos(x)·sin(y))/(cos(x)·cos(y))/(cos(x)·cos(y) - sin(x)·sin(y))/(cos(x)·cos(y)) = (tan(x) + tan(y))(1 - tan(x)·tan(y)

∴ tan(x + y) = (tan(x) + tan(y))(1 - tan(x)·tan(y)

6 0

3 years ago

Read 2 more answers

What is the price of one crate of flowers?

pickupchik [31]

Answer:

$ 2.50

This is the right answer for ed2020

4 0

3 years ago