Answer:
<em> n = 13 </em>
Step-by-step explanation:
= 
+ (n - 1)d
= 3 + 7(n - 1) (for the first AP)
= 63 + 2(n - 1) ( for the second one)
3 + 7(n - 1) = 63 + 2(n - 1)
3 + 7n - 7 = 63 + 2n - 2
5n = 65
<em>n = 13</em>
The solution to the problem is as follows:
2x² - 7x = 3 can be re-written as 2x² - 7x - 3 = 0
<span>
Either by completing the square or using the quadratic formula this can be solved . </span>
<span>
Let's complete the square. </span>
<span>
2x² - 7x - 3 = 2(x² - 3.5x - 1.5) = 2(x - 1.75)² - 9.125....then we can put </span>
2(x - 1.75)² = 9.125 : (x - 1.75)² = 9.125/2 = 4.5625
x - 1.75 = √4.5625 ≈ ± 2.14
<span>x = 1.75 ± 2.14 .....thus x ≈ 3.89 and x ≈ - 0.39
</span>
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Answer:
Hence the value of this perpetuity on January 1, 1995 will be $55993.18404
Step-by-step explanation:
Answer:
a^4+2ab^2+b^4+a^16+2ab^8+b^16
Step-by-step explanation:
(a^2+b^2)^2+(a^8+b^8)^2
(a^2+b^2)^2=(a^2+b^2)(a^2+b^2)
=a^2(a^2+b^2)+b^2(a^2+b^2)
=a^4+(ab)^2+(ba)^2+b^4
=a^4+2ab^2+b^4
(a^8+b^8)^2=(a^8+b^8)(a^8+b^8)
=a^8(a^8+b^8)+b^8(a^8+b^8)
=a^16+(ab)^8+(ba)^8+b^16
=a^16+2ab^8+b^16
(a^2+b^2)^2+(a^8+b^8)^2=(a^4+2ab^2+b^4)+(a^16+2ab^8+b^16)
the answer is a^4+2ab^2+b^4+a^16+2ab^8+b^16
i think it is simplified answer
