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3 years ago

The fifth root of x cubed y squared z

Mathematics

1 answer:

vitfil [10]3 years ago

7 0

$= {x}^{ \frac{3}{5} } {y}^{ \frac{2}{5} } z^{ \frac{1}{5} }$

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What is the circumference and area of a circle of 2.1??

EleoNora [17]

I believe it is 5.14 :)

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3 years ago

Lee wants to place 48 photographs on a wall at school. He puts the photographs into 8 equal rows. How many photographs are in ea

yan [13]

There are 48 photographs in total and he puts them inn 8 equal rows. With this, you have to divide the total amount of photographs (48) by the amount of equal rows (8) to see how many photographs are in each row.

48/8 = 6 photographs in each row.

To check, you can simply do the inverse operation which would be:

6 x 8 = 48

As you can see, the total of 48 still remains.

The answer is:

There are 6 photographs in each row.

4 0

3 years ago

Oxana [17]

Answer:

Step-by-step explanation:

$a(n) = a1 *(1.25)^{(n-1)}$

$a(1) = 5$

$a(2) = 5*(1.25)^{(2-1)}\\a(2) = 5*(1.25)^{1}\\a(2) = 5*(1.25)\\a(2) = 6.25$

$a(3) = 5 * (1.25)^{(3-1)} \\a(3) = 5 * (1.25)^{2}\\a(3) = 5 * 1.565\\a(3) = 7.813$

$a(4) = 5* (1.25)^{(4-1)}\\ a(4) = 5* (1.25)^{3}\\a(4) = 5* 1.953\\a(4) = 9.766$

$a(5) = 5 * (1.25)^{(5-1)}\\a(5) = 5 * (1.25)^{4}\\a(5) = 5 * 2.441\\a(5) = 12.207$

$a(6) = 5 * (1.25)^{5}\\a(6) = 5 * 3.052\\a(6) = 5 * 3.0517\\a(6) = 15.259$

$a(1) = 5$

$a(2) = 6.25$

$a(3) = 7.813$

$a(4) = 9.766$

$a(5)=12.207$

$a(6)=15.259$

3 0

3 years ago

Suppose two fractions are both less than 1. Can their sum be greater than 1? greater than 2?

blagie [28]

Their sum can be greater than 1 but it would be less than 2.

The biggest fraction which is less than 1 is 0.99

Sum of 0.99 + 0.99 = 1.98, which is greater than 1 but less than 2.

6 0

3 years ago

Read 2 more answers

Factor 8X squared + 10x + 2

mojhsa [17]

Answer:

2(4x + 1)(x + 1)

Step-by-step explanation:

Given

8x² + 10x + 2 ← factor out 2 from each term

= 2(4x² + 5x + 1)

To factor the quadratic

Consider the factors of the product of the coefficient of the x² term and the constant term which sum to give the coefficient of the x- term

product = 4 × 1 = 4 and sum = + 5

The factors are + 1 and + 4

Use these factors to split the x - term

4x² + x + 4x + 1 ( factor the first/second and third/fourth terms )

= x(4x + 1) + 1 (4x + 1) ← factor out (4x + 1)

= (4x + 1)(x + 1), thus

4x² + 5x + 1 = (4x + 1)(x + 1) and

8x² + 10x + 2 = 2(4x + 1)(x + 1) ← in factored form

3 0

4 years ago