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kogti [31]
3 years ago
10

. 4 ÷ 5 can be written as a fraction represented by which of the following? A. 5 × 4 B. 4⁄5 C. 4 × 5 D. 5⁄4

Mathematics
2 answers:
Paraphin [41]3 years ago
7 0

The answer is B. 4/5

Volgvan3 years ago
4 0
The answer is B. 4/5
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Subtract <br> 6 2/3 - 4 4/9
Orlov [11]

6 2/3 = 20/3 = 60/9

4 4/9 = 40/9

60/9 - 40/9 = 20/9 = 2 2/9

5 0
3 years ago
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Krissi has $14 in the bank and earns $8 a day. John has 35$ and earns $5 a day when will krissi have more money?
SOVA2 [1]

Answer: 8 days

Step-by-step explanation:

K=14+8x

J=35+5x

when K=J they will have the same amount

14+8x=35+5x

8x=21+5x

3x=21

x=7 days until they have the same amount- 8 days until she has more

5 0
3 years ago
3. Two cars are parked, 150m apart, and on opposite sides of a building. A camera on the top of the building rotates and can vie
allsm [11]

Answer:

<em>The building is 61.5 m tall</em>

Step-by-step explanation:

The image below is a diagram where all the given distances and angles are shown. We have additionally added some variables:

h = height of the building

a, b = internal angles of each triangle

x  = base of each triangle

The angles a and b can be easily found by subtracting the given angles from 90° since they are complementary angles, thus:

a = 90° - 37° = 53°

b = 90° - 42° = 48°

Now we apply the tangent ratio on both triangles separately:

\displaystyle \tan a=\frac{\text{opposite leg}}{\text{adjacent leg}}

\displaystyle \tan 53^\circ=\frac{150-x}{h}

\displaystyle \tan 48^\circ=\frac{x}{h}

From the last equation:

x=h.\tan 48^\circ

Substituting into the first equation:

\displaystyle \tan 53^\circ=\frac{150-h.\tan 48^\circ}{h}

Operating on the right side:

\displaystyle \tan 53^\circ=\frac{150}{h}-\tan 48^\circ

Rearranging:

\displaystyle \tan 53^\circ+\tan 48^\circ=\frac{150}{h}

Solving for h:

\displaystyle h=\frac{150}{\tan 53^\circ+\tan 48^\circ}

Calculating:

h = 61.5 m

The building is 61.5 m tall

5 0
3 years ago
Find the zeros of the function.<br><br> f(x) = 9x2 + 6x - 8
jeyben [28]
Just set it equal to zero and solve using the quadratic equation.
7 0
3 years ago
Read 2 more answers
Find the dimensions of a closed right circular cylindrical can of smallest surface area whose volume is 128pi cm^3
Ratling [72]
The surface area of a cylindrical can is equal to the sum of the area of two circles and the body of the cylinder: 2πr2 + 2πrh. volume is equal to π<span>r2h.

V = </span>π<span>r2h = 128 pi
r2h = 128 
h = 128/r2

A = </span><span>2πr2 + 2πrh
</span>A = 2πr2 + 2πr*(<span>128/r2)
</span>A = 2πr2 + 256 <span>π / r
</span><span>
the optimum dimensions is determined by taking the first derivative and equating to zero.

dA = 4 </span>πr - 256 <span>π /r2 = 0
r = 4 cm
h = 8 cm
</span><span>

</span>
4 0
3 years ago
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