PLEASE HELP ASAP!!! heres the screenshot... please answer with two senteces! srry it is sideways :(
1 answer:
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Answer:
68.26% of the parts will have lengths between 3.8 in. and 4.2 in.
Step-by-step explanation:
The lengths of a lawn mower part are approximately normally distributed
Standard deviation =
We are supposed to find What percentage of the parts will have lengths between 3.8 in. and 4.2 in . i.e. P(3.8<x<4.2)
Formula :
At x = 3.8
Z=-1
Refer the z table for p value
p value =0.1587
At x =4.2
Z=1
Refer the z table for p value
p value =0.8413
P(3.8<x<4.2)=P(x<4.2)-P(x<3.8)=0.8413-0.1587=0.6826
So, 68.26% of the parts will have lengths between 3.8 in. and 4.2 in.