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ololo11 [35]
3 years ago
5

Zachary's final project for a collage course took a semester to write and had 95,234 words. Zachary wrote 35,295 words he first

month and 19,240 words the second month
Mathematics
1 answer:
Nina [5.8K]3 years ago
6 0
Okay so I don't know what you're trying to find out here, but if you're trying to find out how many words he has left after writing those two months, all you have to do is add. 35, 295 + 19, 240 and should get 54, 535. Then you subtract 95,234 - 54,535 and get 40,699.. So Zachary has 40,699 words left to write
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<span>3x + y = 9 (I)
</span><span>y = –4x + 10 (II)
------------------------
</span>\left \{ {{3x + y = 9 } \atop {y = -4x + 10 }} \right.

Pass the incognito "4x" to the first term, changing the signal when changing sides.
<span>-------------------------
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</span>\left \{ {{3x + y = 9.(-1)} \atop {4x + y = 10 }} \right.<span>

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</span>\left \{ {{- 3x - \diagup\!\!\!\!y =-9} \atop {4x + \diagup\!\!\!\!y = 10}} \right.     &#10;
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</span>\left \{ {{- 3x = - 9} \atop {4x = 10}} \right.<span>

-----------
</span>\boxed{x = 1}<span><span>

</span></span><span>Substitute in equation (I) to find the value of "Y".

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Answer:
\boxed{\boxed{ \left \ {{x=1} \atop {y=6}} \right. }}

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