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PIT_PIT [208]
3 years ago
11

How do you find the parameterization of a helix?

Mathematics
1 answer:
Marina CMI [18]3 years ago
7 0

Answer:

\left\{\begin{array}{l}x=r\cos t\\ \\ y=r\sin t\\ \\z=at\end{array}\right.

Step-by-step explanation:

A <u>helix</u> is a curve for which the tangent makes a constant angle with a fixed line. The shortest path between two points on a cylinder (one not directly above the other) is a fractional turn of a helix, as can be seen by cutting the cylinder along one of its sides, flattening it out, and noting that a straight line connecting the points becomes helical upon re-wrapping (see attached diagram for helix).

The parametrization for the helix is

\left\{\begin{array}{l}x=r\cos t\\ \\ y=r\sin t\\ \\z=at\end{array}\right.,

where r is the radius of the helix, a is the constant, and t\in [0,2\pi ) is the parameter

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