To the nearest inch it'll be
d×3.14=63
= 20 inches
Here we must see in how many different ways we can select 2 students from the 3 clubs, such that the students <em>do not belong to the same club. </em>We will see that there are 110 different ways in which 2 students from different clubs can be selected.
So there are 3 clubs:
- Club A, with 10 students.
- Club B, with 4 students.
- Club C, with 5 students.
The possible combinations of 2 students from different clubs are
- Club A with club B
- Club A with club C
- Club B with club C.
The number of combinations for each of these is given by the product between the number of students in the club, so we get:
- Club A with club B: 10*4 = 40
- Club A with club C: 10*5 = 50
- Club B with club C. 4*5 = 20
For a total of 40 + 50 + 20 = 110 different combinations.
This means that there are 110 different ways in which 2 students from different clubs can be selected.
If you want to learn more about combination and selections, you can read:
brainly.com/question/251701
Nineteen and two hundred and thirty eight thousandths
(-3,5)(1,-15)
slope = (-15 - 5) / (1 - (-3) = -20/4 = -5
y = mx + b
slope(m) = -5
use either of ur points...(-3,5)...x = -3 and y = 5
now we sub and find b, the y int
5 = -5(-3) + b
5 = 15 + b
5 - 15 = b
-10 = b
so ur equation is : y = -5x - 10....or 5x + y = -10
