Answer:
Yes, P(A) = P(A|B)
Step-by-step explanation:
The context of the question is incomplete but I've assumed logically what it might be;
Whether a traveller flies or doesn't fly to their destination is unrelated to whether they home share or not;
Therefore, they are independent;
Independent events are events where the outcome of one event has no effect on the probabilities of the outcomes from a second event;
This can be represented mathematically as: P(A) = P(A|B);
The corollary of this is P(B) = P(B|A);
A common example easily understood would be if you flip a coin, there is a 50% chance of heads and 50% chance of tails;
If I flip and gets a heads first, the probability of getting a heads or tails on the second, third or tenth flip is going to be unchanged, i.e. 50% chance of heads and 50% chance of tails
This is the answer!! Also I use Photomath to help with my hw!
Answer:algebra ok
Step-by-step explanation:
An easy way to find this is to look at the cross section, and see where the lines meet
Answer:
1.16777216
2.−16807 x (−13841287201)
3.11390625
4.100000000000
5.13060694016
6.274877906944 x^2
7.9 x
8.x⋅8x+6
hope this helps :)
Step-by-step explanation:
