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ella [17]
3 years ago
9

Factor completely.

Mathematics
1 answer:
yKpoI14uk [10]3 years ago
7 0

Answer:

(m - n) (m + n) (m^2 + n^2)

Step-by-step explanation:

Factor the following:

m^4 - n^4

m^4 - n^4 = (m^2)^2 - (n^2)^2:

(m^2)^2 - (n^2)^2

Factor the difference of two squares. (m^2)^2 - (n^2)^2 = (m^2 - n^2) (m^2 + n^2):

(m^2 - n^2) (m^2 + n^2)

Factor the difference of two squares. m^2 - n^2 = (m - n) (m + n):

Answer:  (m - n) (m + n) (m^2 + n^2)

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Step-by-step explanation:

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Answer:

Account B

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Step-by-step explanation:

#We determine the compounded amount after 10 years for each account using the formula:

A=P(1+i_m)^n, i_m=(1+i/m)^m-1, m-compoundings \ per \ year

#For account A:

Given principal is $16,000, i=3% and n=10, m=4:

(1+i_m)=(1+i/m)^m\\\\=(1+0.03/4)^4=1.03034\\\\\therefore A=16000(1.03034)^{10}\\\\=21573.75

#For account B:

Given principal is $16,000, i=3% and n=10, m=12:

(1+i_m)=(1+i/m)^m\\\\=(1+0.03/12)^{12}=1.03042\\\\\therefore A=16000(1.03042)^{10}\\\\\\\\=21589.66

We compare the amounts after 10 years and get the difference:

B>A\\\\B-A=21589.66-21573\\\\=\$15.91

Hence, account B has the most value after 10 years and has a value of $21,589.66

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