Hey there!!
11 - total
sets of 4
1 set - 4
2nd set - 4
3 rd set - 4
but now, the total would be 12
So, the total number of set = 2
And left overs - 3
Hope helps!
Answer:
By using the pythagorean theorem a^2 + b^2 = c^2
D is the correct answer Where PQ
= √15^2+√19^2
=√ 225 + √361
= √ 586
Length of PQ = √586 = 24.2074368738(ans)
(x-6)(x+6)
Step-by-step explanation:
two n-gons hcogxigvugbu
x=10
Hope it helps please mark brainliest