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Crazy boy [7]
3 years ago
7

F(x)=|x-5|+10 then what’s the Vertex?

Mathematics
1 answer:
mart [117]3 years ago
7 0

Answer:

To find the x x coordinate of the vertex, set the inside of the absolute value x−5 x - 5 equal ... Add 5 5 to both sides of the equation.

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SOLVE THIS PUZZLE PLEASE
kakasveta [241]

Answer:

1) Median

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3 years ago
Need Help Rn!!!
fgiga [73]
It would be 5850 hope you get it right:)
7 0
4 years ago
Name the additive inverse and the multiplicative inverse for the number 2.5
GrogVix [38]

Answer:

i can't see it

Step-by-step explanation:

3 0
3 years ago
Find the points of intersection between x^2+y^2=45 and -3x+y=15​
MatroZZZ [7]

Step-by-step answer:

Given:

Circle C1: x^2+y^2 = 45

Line L1: -3x+y=15

Need to find the points of intersection.

Solution:

basically we need to solve for the roots of equations C1 and L1.

Here, we can use substitution of L1 into C1.

Rewrite L1 as : y=3x+15

substitute into C1:

x^2+(3x+15)^2 = 45

Expand

x^2 + 9x^2+90x+225 = 45

Rearrange terms:

10x^2+90x+180 = 0

Simplify

x^2+9x+18 = 0

Factor

(x+6)(x+3) = 0

so

x=-6 or x=-3

Back-substitute x into L1 to calculate y:

x=-6, y=3*x+15 = 3(-6)+15 = -3  => (-6,-3)

x=-3, y=3*x+15 = 3(-3) + 15 = 6 => (-3, 6)

Therefore the intersection points are (-6,-3) and (-3,6)

Check using equation C1:

(-6)^2+(-3)^2 = 36+9 = 45  ok

(-3)^2+(6)^2 = 9 + 36 = 45 ok

Check using equation L1:

Point (-6,-3) : y = 3x+15 = 3(-6) +15 = -3  ok

Point (-3,6) : y = 3x+15 = 3(-3)+15 = 6 ok.

4 0
4 years ago
What is the initial value of the function represented by this graph?
Travka [436]

Answer:

2

Step-by-step explanation:

I didn't know what an initial value of a graph was at first until I looked it up online and saw that it's basically the y-intercept ,so the y-intercept of the graph would be the value or number that the line is hitting in the y - axis and that would be 2 :-)

6 0
3 years ago
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