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8_murik_8 [283]
3 years ago
9

Value for X^2 left for 95% confidence interval when n=18

Mathematics
1 answer:
tatuchka [14]3 years ago
7 0
Given that n = 18, then the degree of freedom is n - 1 = 17.

From the table of Chi Square (X^2)

The value of (X^2) to the left for 95% confidence interval given a degree of freedom of 17 is 8.672
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