Given:
Consider the expression is
To find:
The value of given expression using a suitable identity.
Solution:
We have,
Using the identity 
, we get
Therefore, the value of the given expression is .
Your answer is C, not B.
-3x + 4 + 2x -2 combined like terms.
-1x + 2
-x - 2. Simple Math.
You need the percentages to answer the question
Based on the information of the table, you have:
1. The ratio is 105/150. By simplifying you get for the ratio 7/10.
2. The students that prefer action movies are 75+90 = 165 and the total numbe of students is 180+240 = 420. Then, the fraction of students who prefer action movies is:
165/420 = 11/28
3. The fraction of seventh graders students that prefer action movies is:
75/180 = 5/12
4. The percent of student that prefer comedy is:
105 + 150 = 255 total student that prefer comedy
420 total number of students
the fraction is:
(x/100)420 = 255
solve for x:
x = 255(100/420)
x = 60.71
the percent of students is 60.71%
5. The percent of eighth graders student who prefer action moveis is:
(x/100)240 = 90
x = 90(100/240)
x = 37.5
the percent of students is 37.5%
6. To determine which from the given grades has the greatest percent of student that prefer action movies, calculate the percent of student in seventh-grade:
(x/100)180 = 75
x = 75(100/180)
x = 41.66
the percent of student is 41.66%
then, seventh grade has the greatest percent of student that prefer action movies.
The answer: 7 * 1,829 = " 12,803 " .
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<span>The following is the explanation—"in expanded form" — (as per the specfic instructions— within this very question—as to how to get the answer:
</span>____________________
Given: 7 * 1,829 = ? ; Find the solution; using "expanded form" :
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(7 * 9 = 63 ) ; +
(7 *20 = 140) ; +
(7 * 800 = 5,600) ; +
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(7 * 1,000 = 7,000) ;
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Now, add the the values together to solve the problem:
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→ 7 * 1,829 = 63 + 140 + 5,600 + 7,000 ;
{ = 203 + 5,600 + 7,000 } ;
{ = 5,803 + 7,000 } ;
= 12,803 ; which is the answer.
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Alternately, write out the steps as follows—using "expanded form":
________________________________________________
→ 7 * 1,829 = ?
________________________________________________
→ 7 * 1,829 = (7*9) + (7*20) + (7*800) + (1,000) ;
________________________________________________
→ 7 * 1,829 = 63 + 140 + 5,600 + 1,000 ;
{ = 203 + 5,600 + 7,000 } ;
{ = 5,803 + 7,000 } ;
= 12,803 ; which is the answer.
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→ {Now, is our obtained answer: "12,803" ; the "correct answer"—to the problem: " 7 * 1,829 " ;} ??
→ Let us check: {Note: " 7 * 1,829 " ; is the same as: ↔ " 1,829 * 7 " .}.
→ Using a calculator, does: "7 * 1829 = ? 12,803" ?? ; Yes! ;
→ &, for that matter; does: " 1829 * 7 =? 12,803" ?? ; Yes! .
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Furthermore, let us check, using the "traditional format" ;
→ Does: "1,829 * 7 =? 12,803 ?? " ;
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{NB: We are multiplying 2 (TWO) numbers together; & 1 (ONE) of these 2 [TWO] numbers is a "1-digit" ["single-digit"] number; & the "OTHER" multiplicand is a "multiple-digit" [specifically, a"4-digit"] number.}.
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NB: Yes; using a calculator is sufficient. Below, I simply provide an alternate method to confirm whether our "obtained value" is correct.
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→ Does: "7 * 1,289 = ? 12,803" ?? ;
→ Using the "traditional method"; let us check; as follows:
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₅ ₂ ₆
→ 1, 829
<span> <u> * 7 </u> </span>
12 8 03 ;
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So; does: "12,803 =? 12,803" ?? ; YES!
→ This "traditional method" shows that: "7 * 1,829" ; does, in fact, equal: "12,803".
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{NB: Explanation of the steps used in solving the aforementioned problem using the "traditional method"—just for clarification and confirmation} :
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→Start with: "7*9= 63" ; Write down the "3" & 'carry over' the "6" ; {Note the small-sized digit, "6"; written on top of the "2"; {commonly done—to keep track);
→Then; "7*2 = 14" ; then add the "small digit 6"; to the "14" ; →"14+6 =20" ;
Write down the "0" ; & 'carry over' the "2" ; {Note the "small-sized digit, "2"; written over the "8"; (commonly done—to keep track);
→ Then; "7*8 = 56" ; then add the "small digit 2"; to the "56"; → "56+2 = 58" ; Write down the "8" ; & 'carry over' the "5" ; {Note the "small-sized digit", "5" ; written over the "1" ; (commonly done—to keep track);
→Then; "7*1 = 7" ; then add the "small digit 5"; to the "7" ; → "7+5 = 12" ; Write down the "12" ; in its entirety—since are no digits left [in the multiplicand, "1,829"] ; to "carry over".
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We get: "12,803" ; which =? "12,803" ?? ;→Yes!
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I hope my explanation of how to solve "7 * 1,829" ; using the "expanded form" is helpful. Also, i hope my explanation—albeit lengthy— of confirming that [<em>our</em>] "correctly obtained value"—which is: "12,803"— is of some help.
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