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shepuryov [24]
3 years ago
10

NEED ANSWER QUICK - NO FALSE ANSWERS BRAINLIEST WILL BE GIVEN

Mathematics
2 answers:
fenix001 [56]3 years ago
6 0

Answer:

f(-2) =2

Step-by-step explanation:

f(-2) means find the y value when x=-2

The y value is 2 when x=-2

MA_775_DIABLO [31]3 years ago
3 0
F(-2)=2
Hope that helps :)
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Ok, I have no idea what the answer is but you can use desmos graphing calculator because that really helps :)
5 0
3 years ago
If I made 80 muffins and brought 2/5 of them to work how many muffins did I leave at home?
victus00 [196]

Answer:

32

Step-by-step explanation:

6 0
3 years ago
A circle is defined by x^2+y^2+2gx+2fy-15=0. The gradient of the tangent to the circle at the point (3,2) is -1/2. Find the valu
natita [175]

Answer:

  (g, f) = (-1, 2)

Step-by-step explanation:

The equation can be put into standard form:

  (x^2 +2gx) +(y^2 +2fy) = 15

  (x^2 +2gx +g^2) +(y^2 +2fy +f^2) = 15 +g^2 +f^2

  (x +g)^2 +(y +f)^2 = 15 +g^2 +f^2 . . . . equation in standard form

The point (3, 2) is on the circle, so one of the equations we have is ...

  (3+g)^2 +(2 +f)^2 = 15 +g^2 +f^2

  9 +6g +g^2 +4 +4f +f^2 = 15 +g^2 +f^2

  6g +4f = 2 . . . . . . . subtract g^2 +f^2 +13

  3g +2f = 1 . . . . . . . divide by 2

__

A line through the center of the circle is perpendicular to the tangent at the point of tangency. That line will have a slope that is the negative reciprocal of the tangent's slope: m = -1/(-1/2) = 2. Then in point-slope form the equation of the line through the center is ...

  y -2 = 2(x -3)

  2x -y = 4 . . . . rearrange to standard form

The point at the center of the circle, (-g, -f), satisfies this equation, so we have another relation for f and g:

  2(-g) -(-f) = 4

  2g -f = -4 . . . . . . multiply by -1

Adding twice this equation to the one above, we have ...

  2(2g -f) +(3g +2f) = 2(-4) +(1)

  7g = -7 . . . . . . . . . simplify

  g = -1 . . . . . . . . . . divide by 7

  f = 2g +4 = 2(-1) +4 = 2 . . . find the corresponding value of f

The values of f and g are: f = 2 and g = -1.

7 0
3 years ago
Find the perimeter of quadrilateral ABCD. Round to the nearest tenth.
Olegator [25]

Answer:

14.6 units

Step-by-step explanation:

AB = \sqrt{(1-3)^2+(3-5)^2}

AB =\sqrt{8}

BC = \sqrt{(3-1)^2+(-1-3)^2}=\sqrt{20}

CD = \sqrt{(5-3)^2+(3-(-1))} = \sqrt{20}

DA = \sqrt{(5-3)^2+(3-5)^2} = \sqrt{8}

Primeter = \sqrt{8} + \sqrt{20} + \sqrt{20} +\sqrt{8} = 14.6

4 0
3 years ago
find the slope of the line passing through each of the following pairs of points and draw the graph of the line. (-1,4),(-1,-3)
Ksju [112]

Answer:

2/5

Step-by-step explanation:

(-3-(-1))/(-1-4)= 2/5

4 0
3 years ago
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