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lbvjy [14]
3 years ago
14

Final question for my homework

Mathematics
2 answers:
zubka84 [21]3 years ago
6 0


20% = 0.20

- - 0.20 = 0.80

28*0.80 = 22.40

22.40-2 = 20.40

it cost $20.40

valkas [14]3 years ago
5 0

<span><span>First, you need to find out what 20% of $28 is so you can subtract if from the price of the necklace.
</span> $28 x .20 = $5.60</span>

<span><span>Now we can subtract the $5.60 from $28.
</span> $28 – $5.60 = $22.40</span>

<span><span>Now we can subtract the $2 coupon.
</span> $22.40 - $2 = $20.40</span>

So, the price that Jane will pay for the necklace is $20.40


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Answer:

Step-by-step explanation:

This is a test of 2 independent groups. The population standard deviations are not known. Let μ1 be the mean compression strength from the extra carbonation of strawberry drink and μ2 be the mean compression strength from the extra carbonation of cola.

The random variable is μ1 - μ2 = difference in the mean compression strength from the extra carbonation of strawberry drink and the mean compression strength from the extra carbonation of cola.

We would set up the hypothesis.

The null hypothesis is

H0 : μ1 = μ2 H0 : μ1 - μ2 = 0

The alternative hypothesis is

H1 : μ1 < μ2 H1 : μ1 - μ2 < 0

This is a left tailed test.

Since sample standard deviation is known, we would determine the test statistic by using the t test. The formula is

(x1 - x2)/√(s1²/n1 + s2²/n2)

From the information given,

x1 = 530

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t = (530 - 533)/√(23²/10 + 16²/10)

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The formula for determining the degree of freedom is

df = [s1²/n1 + s2²/n2]²/(1/n1 - 1)(s1²/n1)² + (1/n2 - 1)(s2²/n2)²

df = [23²/10 + 16²/10]²/[(1/10 - 1)(23²/10)² + (1/10 - 1)(16²/10)²] = 6162.25/383.752

df = 16

We would determine the probability value from the t test calculator. It becomes

p value = 0.0097

Since alpha, 0.05 > than the p value, 0.0097, then we would reject the null hypothesis. Therefore, at 5% significance level, the data suggests that the extra carbonation of cola results in a higher average compression strength.

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