There are 4 possible letters to start with.
The pass word is 3 letters long.
The first letter can be A, B, C, D = 4 different letters.
The 2nd letter can be 4 - 1 = 3 letters ( Can't have repeats)
The 3rd letter can be 3-1 = 2 letters ( no repeats)
Number of possible passwords = 4 x 3 x 2 = 24
Answer:
$80.24
Step-by-step explanation:
I got 6.012 times 10^3
I'm not sure how to make it into decimal form but maybe that number can help you. Hopefully it's correct