Question

What is the remainder when (4x3 + 2x2 − 18x + 38) ÷ (x + 3)? 2 12 96 110

Answer 1

°°°4°°°2°°°-18°°°°°°38
•|
-3|°°°-12°°°30°°°°°-36
------------------------------'
°°°4°° -10 12°°°°° °°2
remainder=2

Answer 2

Answer:  First Option is correct.

Step-by-step explanation:

Since we have given that

$(4x^3+2x^2-18x+38)\div(x+3)$

We will apply the "Remainder Theorem ":

So, first we take

$g(x)=x+3=0\\\\g(x)=x=-3\\\\and\\\\f(x)=4x^3+2x^2-18x+38$

So, we will put x=-3 in f(x).

$f(-3)=4\times (-3)^3+2\times (-3)^2-18\times (-3)+38\\\\f(-3)=-108+18+54+38\\\\f(-3)=2$

So, Remainder of this division is 2.

Hence, First Option is correct.