The first one is true, so is the fourth one. The second one is not true and I'm not sure about the 3rd one, you would have to write them all out in numerical order and find the one in the middle
Answer:
2/3
Step-by-step explanation:
take 30/45 and divide by 15 and you get 2/3
Answer:
Remember that for a square of height H and length L, the area will be:
A = H*L
In this case, we know that the height is H = 4 units.
And the area is up to 48 square units
This means that the maximum possible area of this rectangle is 48 square units.
Then we have:
A ≤ 48 square units.
And we also could add:
0 square units < A ≤ 48 square units.
Now we can replace A by H*L = L*(4units)
0 square units < L*(4 units) ≤ 48 square units.
Now we need to divide all 3 sides by 4 units.
(0 square units)/(4 units) < L ≤ (48 square units)/(4 units)
0 units < L ≤ 12 units.
This is the range of lengths that Saritha can use to reconstruct the rectangle.
Now if we define b as the length of the bases, then we will use:
b = height = 4units.
Then:
1b = 4units.
(1 b/4units) = 1
This means that:
12 units = (12 units)*1 = (12 units)*(1 b/4units) = (12/4) b = 3 b
Then the range of possible values of L is:
0b < L ≤ 3b
Answer:
This isn't really an answer,but I used to use an app called "Photomath" it shows you the answer as well as the work.
Step-by-step explanation:
