Answer:
The volume of the figure is ![(\frac{l^{3}}{3})[\frac{\pi }{2}-1]\ units^{3}](https://tex.z-dn.net/?f=%28%5Cfrac%7Bl%5E%7B3%7D%7D%7B3%7D%29%5B%5Cfrac%7B%5Cpi%20%7D%7B2%7D-1%5D%5C%20units%5E%7B3%7D)
Step-by-step explanation:
we know that
The volume of the figure is equal to the volume of the cone minus the volume of the square pyramid
step 1
Find the volume of the cone
The volume of the cone is equal to

we have
----> the diagonal of the square base of pyramid is equal to the diameter of the cone

substitute

step 2
Find the volume of the square pyramid
The volume of the pyramid is equal to

where
B is the area of the base
h is the height of the pyramid
we have


substitute


step 3
Find the volume of the figure
![\frac{1}{6}\pi (l)^{3}\ units^{3}-\frac{1}{3}l^{3}\ units^{3}=(\frac{l^{3}}{3})[\frac{\pi }{2}-1]\ units^{3}](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B6%7D%5Cpi%20%28l%29%5E%7B3%7D%5C%20units%5E%7B3%7D-%5Cfrac%7B1%7D%7B3%7Dl%5E%7B3%7D%5C%20units%5E%7B3%7D%3D%28%5Cfrac%7Bl%5E%7B3%7D%7D%7B3%7D%29%5B%5Cfrac%7B%5Cpi%20%7D%7B2%7D-1%5D%5C%20units%5E%7B3%7D)
If you would like to know what is - 13/25 as a decimal, you can calculate this using the following step:
- 13/25 = - (4*13)/100 = - 52/100 = - 0.52
Result: - 13/25 as a decimal is - 0.52.
Answer:

Step-by-step explanation:
We have that:

Now we can find a+b

Answer:
Statement A is correct about Sam's box and whisker plot.
Step-by-step explanation:
We have been given a box plot and we are asked to find out true statement according to the box plot.
Since we know data represented by box plot is divided in four equal parts.
Upon looking at our box plot we can see that our data is symmetric. It's median is 15, which means half the math assignments have less than 15 problems and half of the math assignments have more than 15 problems.
Interquartile range represents 50% values of data and it is the difference between upper quartile and lower quartile. IQR is not affected by outliers.

Upon substituting given values from box plot we get,

From IQR we can conclude that half of the assignments contained 15 problems or fewer.Therefore, option A is the correct choice.