Question

PLZ HELP ASAP. VERY MUCH NEEDED...

Answer 1

Answer:

$\large \boxed{\text{1.23 g/L}}$

Explanation:

We can use the Ideal Gas Law to calculate the density of the gas.

 pV = nRT

    n = m/M            Substitute for n

  pV = (m/M)RT     Multiply both sides by M

pVM = mRT           Divide both sides by V

  pM = (m/V) RT

     ρ = m/V            Substitute for m/V

  pM = ρRT            Divide each side by RT

$\rho = \dfrac{pM }{RT}$

Data:

The gas is N₂ at STP (0 °C and 1 bar)

p = 1 bar

M = 28.01 g/mol

R = 0.083 14 bar·L·K⁻¹mol⁻¹

T = 0 °C = 273.15 K

ρ = (1 × 28.01)/(0.083 14 × 273.15) = 1.23 g/L

$\text{The density of the gas is \large \boxed{\textbf{1.23 g/L}} }$

It appears that you are using the old definition of STP. Standard pressure has been defined as 1 bar since 1982.