A country's population in 1995 was 184 million. in 2002 it was 188 million. estimate the population in 2006 using exponential gr
owth formula. round your answer to the nearest millions?
1 answer:
P = A.e^(r.t) is the population growth formula, where A is the initial population in a given year, exponent "r" =growth rate and exponent t = time
A₍₁₉₉₅₎ = 184 Mil. after t = 7 years, P₍₂₀₀₂₎ = 188 Mil
Let's calculate te growth rate:
P₍₂₀₀₂₎ = A₍₁₉₉₅₎.e^rt
188 = 184.e(^7r)
188/184 = e^(7r)
ln(188/184) = 7.r.lne
0.0215 = 7.r and r = 0.0030 = 0.3%
Population in 2006
P₍₂₀₀₆₎ = P₍₂₀₀₂₎.e⁽⁰.⁰⁰³ˣ⁴
P₍₂₀₀₆₎ = 188.e⁰.⁰¹² = 190.2 Mil
You might be interested in
Move the decimal to the right 4 places to get 4 x 10^-4 which reads four times ten to the negative fourth power
Answer:
-1.9 Should be correct!
Step-by-step explanation:
I’m assuming you’re saying with an exponent. 7x^2+5
Genes, "characteristic of the offspring" (google web)
I just noticed I said it’s wrong .. I don’t know the answer