4 years ago

Write an algebraic expression for the word expression.

2 answers:

8 0

1. X+9
2. B-5+6
3. 15+ 5 multiply V
4. 2-3 multiply K
5. 12 divide (H+2)
6. M/7
7. 2 multiply F + 9
8. 6- (X-3)
9. G/3 - 10
10.4+ (4 multiply 5 multiply A)
11. R-S + 14
Hope this answer help you

max2010maxim [7]4 years ago

6 0

1. x+9
2. (b-5)+6
3. 15+5v
4. 2/3k

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Test the claim below about the mean of the differences for a population of paired data at the level of significance α Assume the

Evgen [1.6K]

Complete Question

The complete question is shown on the first uploaded image

Answer:

The correct option is F

$t = 1.17$

$t_ {\alpha , df} =t_ {0.10 , 8} = 1.86$

Since the test statistics is outside the rejection region , we fail to reject the null hypothesis ,There is no statistically significant evidence to reject the claim

Step-by-step explanation:

From the question we are told that

The claim is $\mu = 0$

Hence

The null hypothesis is $H_o : \mu = 0$

The alternative is $H_a : \mu \ne 0$

Generally the test statistics is mathematically represented as

$t = \frac{\= d - \mu_d }{ \frac{s_d}{ \sqrt{n} } }$

=> $t = \frac{3.5 -0 }{ \frac{8.94}{ \sqrt{9} } }$

=> $t = 1.17$

Generally the degree of freedom is mathematically represented as

$df = n- 1$

$df = 9 - 1$

$df = 8$

From the student t-distribution table the critical value of $\alpha$ at a degree of freedom of 8 is

$t_ {\alpha , df} =t_ {0.10 , 8} = 1.86$

Since the $t_ {\alpha , df}$ is outside the rejection region , we fail to reject the null hypothesis ,There is no sufficient evidence to reject the claim