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3 years ago

Help me anwser!I really need help

Mathematics

1 answer:

Viefleur [7K]3 years ago

5 0

Use a calculator to answer

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Just answr. I’ll give lot of point

KonstantinChe [14]

Answer:

there is no picture but i can try to help you

Step-by-step explanation:

8 0

3 years ago

When 440 junior college students were surveyed, 200 said they have a passport. Construct a 95% confidence interval for the propo

nekit [7.7K]

Sample proportion: 190/425 = 0.45
ME = 1.96*sqrt[0.45*0.55/425] = 0.047
-----
95% CI: 0.45-0.047 < p < 0.45+0.047

7 0

3 years ago

What do the asymptotes represent when we graph the tangent function? Where are they?

Alisiya [41]

Answer:

The asymptotes are the x-values for which the tangent function is not defined. We draw these in to remind us that the function does not cross that line. They are the odd multiples of 90°

7 0

3 years ago

A) Findi

Romashka [77]

Answer:

Part A)

$\displaystyle \frac{dy}{dx}=-\frac{2xy+y^2}{x^2+2xy}$

Part B)

$\displaystyle y=-\frac{5}{8}x+\frac{9}{4}$

Step-by-step explanation:

We have the equation:

$\displaystyle x^2y+y^2x=6$

Part A)

We want to find the derivative of our function, dy/dx.

So, we will take the derivative of both sides with respect to <em>x:</em>

<em /> $\displaystyle \frac{d}{dx}\Big[x^2y+y^2x\Big]=\frac{d}{dx}\big[6\big]$ <em />

The derivative of a constant is 0. We can expand the left:

$\displaystyle \frac{d}{dx}\Big[x^2y\Big]+\frac{d}{dx}\Big[y^2x\Big]=0$

Differentiate using the product rule:

$\displaystyle \Big(\frac{d}{dx}\big[x^2\big]y+x^2\frac{d}{dx}\big[y\big]\Big)+\Big(\frac{d}{dx}\big[y^2\big]x+y^2\frac{d}{dx}\big[x\big]\Big)=0$

Implicitly differentiate:

$\displaystyle (2xy+x^2\frac{dy}{dx})+(2y\frac{dy}{dx}x+y^2)=0$

Rearrange:

$\displaystyle \Big(x^2\frac{dy}{dx}+2xy\frac{dy}{dx}\Big)+(2xy+y^2)=0$

Isolate the dy/dx:

$\displaystyle \frac{dy}{dx}(x^2+2xy)=-(2xy+y^2)$

Hence, our derivative is:

$\displaystyle \frac{dy}{dx}=-\frac{2xy+y^2}{x^2+2xy}$

Part B)

We want to find the equation of the tangent line at (2, 1).

So, let's find the slope of the tangent line using the derivative. Substitute:

$\displaystyle \frac{dy}{dx}_{(2,1)}=-\frac{2(2)(1)+(1)^2}{(2)^2+2(2)(1)}$

Evaluate:

$\displaystyle \frac{dy}{dx}_{(2,1)}=-\frac{4+1}{4+4}=-\frac{5}{8}$

Then by the point-slope form:

$y-y_1=m(x-x_1)$

Yields:

$\displaystyle y-1=-\frac{5}{8}(x-2)$

Distribute:

$\displaystyle y-1=-\frac{5}{8}x+\frac{5}{4}$

Hence, our equation is:

$\displaystyle y=-\frac{5}{8}x+\frac{9}{4}$

5 0

2 years ago

Draw a parallelogram with a base of 3cm and a height of 7cm and shiw howto calculate its area

tia_tia [17]

Answer:

a parallelogram is a rectangle so the sides are 3cm and the other two are 7cm

Step-by-step explanation:

how to calculate the area is u multiply 7 by three and there is your answer

3 0

2 years ago