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LekaFEV [45]
3 years ago
5

Please Help.....'Divide. Write your answer to the simplest form.5/6 divided by 7/10

Mathematics
1 answer:
belka [17]3 years ago
8 0

Answer:

<u>5/6 ÷ 7/10 = 1 4/21</u>

Step-by-step explanation:

<u>How did we solve the problem above? When we divide two fractions, such as 5/6 ÷ 7/10, we flip the second fraction and then we simply multiply the numerators with each other and the denominator with each other.</u>

<u>We also simplify the answers to fraction problems whenever possible.  hope this helps</u>

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Write the slope intercept form of a line that passes<br> through (3, -2) and is 1 to y = x + 3.
zhuklara [117]

Answer:12

Step-by-step explanation:

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4 years ago
Let f(x)=x2−3x−4 . What is the average rate of change from x = 7 to x = 10? Question 6 options: 24 14 66 42
Fed [463]
Just find the slope between the points

basically find (f(10)-f(7))/(10-7)

f(7)=7^2-3(7)-4=49-21-4=24
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slope=(66-24)/(10-7)=42/3=14
average rate of change is 14
8 0
3 years ago
The difference of two numbers is 8. If the sum of the smaller number and the square of the larger number is 148, what is the sma
Mice21 [21]

Answer:

140

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4 0
3 years ago
The first step in determining the solution to the system of equations, y = -x2 - 4x - 3 and y = 2x + 5, algebraically is to set
sweet-ann [11.9K]

Answer:

Combine like terms onto one side of the equation

Step-by-step explanation:

You have

-x^2  -4x  - 3  = 2x + 5

It seems that we should combine like terms to make this equations smaller.

-x^2 - 4x - 3  - 2x  - 5 = 0

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6 0
3 years ago
An archaeologist uses an accelerator mass spectrometer to find the age of a buried branch. At the 68\%68%68, percent confidence
Komok [63]

Answer:

B. 10000 years old, with a margin of error of 400 years

Step-by-step explanation:

Assuming this complete problem: "12. An archaeologist uses an accelerator mass spectrometer to find the age of a buried branch. At the 68% confidence level, the spectrometer estimates that the branch was 10,000 years old with a following could the spectrometer estimate as the age of the branch at the 95% confidence level?"

The possible options are:

A. 9500 years old, with a margin of error of 500 years

B. 10000 years old, with a margin of error of 400 years

C. 9500 years olds, with a margin of error of 50 years

D. 10000 years old, with a margin of error of 40 year

Solution to the problem

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

\bar X represent the sample mean for the sample  

\mu population mean (variable of interest)

s represent the sample standard deviation

n represent the sample size  

The confidence interval for the mean is given by the following formula:

\bar X \pm z_{\alpha/2}\frac{\sigma}{\sqrt{n}}   (1)

The margin of error for this case is given by this formula:

ME= z_{\alpha/2}\frac{\sigma}{\sqrt{n}}

For the first case the confidence was 68% so then \alpha =1-0.68 =0.32 and \alpha/2 =0.16 we can find a critical value on the normal standard distribution that accumulates 0.16 of the area on each tail and this value is z=\pm 0.994, because P(z<-0.944) = 0.16 and P(Z>.944) = 0.16

The margin of error can be expressed like this:

ME = z_{\alpha/2} SE

We can solve for the standard error on this case and we got:

SE = \frac{ME}{z_{\alpha/2}} =\frac{200}{0.994}=201.207

And then for the new confidence interval we need to calculate the new z_{\alpha}. For the first case the confidence was 95% so then \alpha =1-0.95 =0.05 and \alpha/2 =0.025 we can find a critical value on the normal standard distribution that accumulates 0.025 of the area on each tail and this value is z=\pm 1.96, because P(z<-1.96) = 0.025 and P(Z>1.96) = 0.025. So then the new margin of error would be:

ME = z_{\alpha/2} SE = 1.96*201.207=394.366

The estimation for the mean not changes and from the before and new case is 1000 years. So then the best option for this case would be:

B. 10000 years old, with a margin of error of 400 years

And makes sense since a larger confidence interval means a wider interval.

8 0
3 years ago
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