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LekaFEV [45]
4 years ago
5

Please Help.....'Divide. Write your answer to the simplest form.5/6 divided by 7/10

Mathematics
1 answer:
belka [17]4 years ago
8 0

Answer:

<u>5/6 ÷ 7/10 = 1 4/21</u>

Step-by-step explanation:

<u>How did we solve the problem above? When we divide two fractions, such as 5/6 ÷ 7/10, we flip the second fraction and then we simply multiply the numerators with each other and the denominator with each other.</u>

<u>We also simplify the answers to fraction problems whenever possible.  hope this helps</u>

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Line segment JM has endpoints with coordinates -2 and 14 on a number line. Points K and L are on segment JM. K has a coordinate
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B. \frac{25}{64}

Step-by-step explanation:

Please find the attachment.  

We have been given that line segment JM has endpoints with coordinates -2 and 14 on a number line. Points K and L are on segment JM. K has a coordinate of 2 and point L has a coordinate of 8.

The probability that the first point is positioned on JL would be \frac{10}{16} as there are total 10 points on JL as L is at point 8 and J is at point -2 so (8--2=8+2=10). Total number of points on the number line JM is (14--2=14+2=16)  

The probability that second point is not placed on KL would be:

P(\text{The point is not on KL)}=1-\text{probability that point is on KL}

P(\text{The point is not on KL)}=1-\frac{\text{Total points on KL}}{\text{Total points on JM}}

P(\text{The point is not on KL)}=1-\frac{(8-2)}{16}

P(\text{The point is not on KL)}=1-\frac{6}{16}

P(\text{The point is not on KL)}=\frac{16-6}{16}

P(\text{The point is not on KL)}=\frac{10}{16}

\text{The probability of getting 1st point on Jl and second point is not on KL}=\frac{10}{16}\times \frac{10}{16}

\text{The probability of getting 1st point on Jl and second point is not on KL}=\frac{5}{8}\times \frac{5}{8}

\text{The probability of getting 1st point on Jl and second point is not on KL}=\frac{25}{64}

Therefore, our desired probability will \frac{25}{64} and option B is the correct choice.

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