Let "a" and "b" be the two numbers
So a*b=-8 and a+b=-7
Therefore S=-7 and P=-8
Using (x^2)-S+P=0 => (x^2)-(-7)+(-8)=0 => (x^2)+7-8=0
By factorizing we get (x+8)(x-1)=0
So a can be either -8 or 1 and b can be 1 or -8
Meaning that the two numbers are -8 and 1.

6 0

3 years ago

I need help with this plzz

Schach [20]

Answer:

5/2

Step-by-step explanation:

6 0

3 years ago

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The function is y=6x. Find the horizontal asymptote of the curve.

Lynna [10]

Answer:

y=-6x/square root (4x^2-160

Step-by-step explanation:

hope this helps please mark me brainliest

6 0

2 years ago

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Write an equation of the line that is perpendicular to 3x - 4y equals 9 + contains (-4, -5)

Inga [223]

Slope-Intercept Form: y = mx+b, with m = slope and b = y-intercept

So perpendicular lines have slopes that are negative reciprocals to each other, but firstly we need to find the slope of the original equation. The easiest method to find it is to convert this standard form into slope-intercept.

Firstly, subtract 3x on both sides of the equation: $-4y=-3x+9$

Next, divide both sides by -4 and your slope-intercept form of the original equation is $y=\frac{3}{4}x-\frac{9}{4}$

Now looking at this equation, we see that the slope is 3/4. Now since our new line is perpendicular, this means that its slope is -4/3.

Now that we have the slope, plug that into the m variable and plug in (-4,-5) into the x and y coordinates to solve for the b variable as such:

$-5=-\frac{4}{3}*-4+b\\\\-5=5\frac{1}{3}+b\\\\-10\frac{1}{3}=b$

In short, your new equation is y = -4/3x - 10 1/3.

3 0

3 years ago

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