Answer:
thirty and six hundred fifty-nine thousandths
Step-by-step explanation:
Answer:
- After 4 seconds the height is 480 meters.
- The maximum height is 484 meters.
- The ball hits the ground after 10 seconds
Step-by-step explanation:
The height after four seconds is h(4) = -16 * r² + 144*4+160 = 480
The maximum height of the ball is the value it takes at its vertex 'v = -b/2a'. In this case a = -16 and b = 144, so the v = -144/-32 = 4.5. The maximum height of the ball as a result is h(4.5) = -16 (4.5)² + 144*4.5 + 160 = 484
To find the moment the ball hits the ground, we need to find when h takes the value 0 by using the quadratic formula, with a = -16, b = 144 and c = 160.

Since t cant take negative values, then the correct value is 10. The ball hits the ground after 10 seconds.
9514 1404 393
Answer:
∠6 = ∠4 = 84°
∠5 = ∠3 = 96°
Step-by-step explanation:
Angle 4 and the marked angle (84°) are <em>corresponding</em> angles, so are congruent. Angles 4 and 6 are vertical angles, so are congruent.
∠6 = ∠4 = 84°
Angle 3 and the marked angle are a linear pair, so angle 3 is the supplement of 84°:
∠3 = 180° -84° = 96°
Angle 3 and angle 5 are <em>alternate interior </em>angles, so are congruent.
∠5 = ∠3 = 96°
Answer: (7x^2+144)/x^2
Step-by-step explanation:
f(h(x))=
f(12/x)=
(12/x)^2+7=
12^2/x^2 + 7=
144/x^2 +7=
144/x^2 +7*x^2/x^2=
144/x^2+7x^2/x^2=(7x^2+144)/x^2
Answer:
about 15 hours
Step-by-step explanation:
You want to find t such that N(t)=200. Fill in the equation with that information and solve for t.
200 = 400/(1 +399e^(-0.4t))
1 +399e^(-0.4t) = 400/200 = 2 . . . . . multiply by (1+399e^(-0.4t))/200
399e^(-0.4t) = 1 . . . . . . . . . . . . . . . . . . subtract 1
e^(-0.4t) = 1/399 . . . . . . . . . . . . . . . . . .divide by 399
-0.4t = ln(1/399) . . . . . . . take the natural log
t = ln(399)/0.4 ≈ 14.972 . . . . . . . divide by -0.4, simplify
Rounded to tenths, it will take 15.0 hours for half the people to have heard the rumor.