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meriva
3 years ago
7

Altitudes AA1 and BB1 are drawn in acute △ABC. Prove that A1C·BC=B1C·AC

Mathematics
1 answer:
Sophie [7]3 years ago
7 0

Answer:

See the attached figure which represents the problem.

As shown, AA₁ and BB₁ are the altitudes in acute △ABC.

△AA₁C is a right triangle at A₁

So, Cos x = adjacent/hypotenuse = A₁C/AC ⇒(1)

△BB₁C is a right triangle at B₁

So, Cos x = adjacent/hypotenuse = B₁C/BC ⇒(2)

From (1) and  (2)

∴  A₁C/AC = B₁C/BC

using scissors method

∴ A₁C · BC = B₁C · AC

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6 0
3 years ago
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Marie purchased a 29.00 gift. She uses a coupon that offers 30 percent. How much will she spend on the gift after the coupon?
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Answer:

$20.30

Step-by-step explanation:

The usual price of the gift is $29.00

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First, we need to find 30% of $29.00. Then we need to subtract that from original price (29).

Convert percentage to decimal first:

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Now multiply this with 29 to get:

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3 years ago
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4 0
3 years ago
Burnwood Tech plans to issue some $50 par preferred stock with a 8% dividend. A similar stock is selling on the market for $65.
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6.5%

Step-by-step explanation:

The formular used to calculate the cost of preferred stock is:

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8 0
3 years ago
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grin007 [14]
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hope it helps
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