Solve the equation by factoring,2x^2=28-x

Which of the following is equal to 7 1/3?

earnstyle [38]

Answer:

C

Step-by-step explanation:

If the number's a fraction, which this one is, the denominator will always be that little number by the radical, and the whole number will be in the root. Hope this helps!

5 0

4 years ago

Read 2 more answers

Please help!!

timofeeve [1]

Answer:

y = 2/3x

Step-by-step explanation:

So we know, when lines are perpendicular that they share the same slope. The slope in the equation of y = 2/3x + 7 is 2/3x. So, we have our slope. Now, we just need to find our b. We plug in the point that you gave us into the equation y = mx + b.

3 = 2/3(2) + b

we multiply the denominator 3 by 2, then divide that by the numerator 2.

3 = 3 + b

subtract 3 from itself and from the opposite side of the equal side 3.

0 = b

in the end, there is no b for this equation. Our answer is

y = 2/3x

6 0

3 years ago

Which polynomial has (3x + 2) as a binomial factor?

Nuetrik [128]

Answer:

Step-by-step explanation:

If binomial (3x+2) is a factor of some polynomial, then number is this polynomial's root. Check all polynomials:

6x^3+3x^2+4x+2

8 0

3 years ago

Please someone help me

irina1246 [14]

The area of the triangle extension is 12, because the total side length it is on is 18, and the segments to the sides of the triangle are 6 each, meaning 18-12=6, the height of the triangle. The base is given as 4, so 1/2(4x6)=24/2=12.

Add this to the area of the rectangle, 9x18=162, and 162+12=174.

The area is 174.

7 0

4 years ago

Read 2 more answers

Assume that you have a sample of n 1 equals 6, with the sample mean Upper X overbar 1 equals 50, and a sample standard deviati

tigry1 [53]

Answer:

$t=\frac{(50 -38)-(0)}{7.46\sqrt{\frac{1}{6}+\frac{1}{5}}}=2.656$

$df=6+5-2=9$

$p_v =P(t_{9}>2.656) =0.0131$

Since the p value is higher than the significance level given of 0.01 we don't have enough evidence to conclude that the true mean for group 1 is significantly higher thn the true mean for the group 2.

Step-by-step explanation:

Data given

$n_1 =6$ represent the sample size for group 1

$n_2 =5$ represent the sample size for group 2

$\bar X_1 =50$ represent the sample mean for the group 1

$\bar X_2 =38$ represent the sample mean for the group 2

$s_1=7$ represent the sample standard deviation for group 1

$s_2=8$ represent the sample standard deviation for group 2

System of hypothesis

The system of hypothesis on this case are:

Null hypothesis: $\mu_1 \leq \mu_2$

Alternative hypothesis: $\mu_1 > \mu_2$

We are assuming that the population variances for each group are the same

$\sigma^2_1 =\sigma^2_2 =\sigma^2$

The statistic for this case is given by:

$t=\frac{(\bar X_1 -\bar X_2)-(\mu_{1}-\mu_2)}{S_p\sqrt{\frac{1}{n_1}+\frac{1}{n_2}}}$

The pooled variance is:

$S^2_p =\frac{(n_1-1)S^2_1 +(n_2 -1)S^2_2}{n_1 +n_2 -2}$

We can find the pooled variance:

$S^2_p =\frac{(6-1)(7)^2 +(5 -1)(8)^2}{6 +5 -2}=55.67$

And the pooled deviation is:

$S_p=7.46$

The statistic is given by:

$t=\frac{(50 -38)-(0)}{7.46\sqrt{\frac{1}{6}+\frac{1}{5}}}=2.656$

The degrees of freedom are given by:

$df=6+5-2=9$

The p value is given by:

$p_v =P(t_{9}>2.656) =0.0131$

Since the p value is higher than the significance level given of 0.01 we don't have enough evidence to conclude that the true mean for group 1 is significantly higher thn the true mean for the group 2.

4 0

3 years ago