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Kitty [74]
3 years ago
15

Find two integers whose sum is -13 and product is 40

Mathematics
2 answers:
Nastasia [14]3 years ago
7 0
-8 and -5

-8 x -5 = 40
-8 + (-5) = -13
Umnica [9.8K]3 years ago
3 0
Let us say, the numbers are "a" and "b"
their sum is -13
a + b = -13 

their product is 40
a * b = 40 \bf \begin{cases}
a+b=-13\\
a\cdot b=40\implies b=\frac{40}{a}\\
then\\
------------\\
a+\boxed{b}=-13\implies a+\boxed{\frac{40}{a}}=-13
\end{cases}

solve for "a",
what is "b"? well, b = 40/a :)
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