Answer:
X=18
Step-by-step explanation:
(1/2)*x-7 = (1/3)*(x-12) // - (1/3)*(x-12)
(1/2)*x-((1/3)*(x-12))-7 = 0
(-1/3)*(x-12)+(1/2)*x-7 = 0
x/2-1/3*(x-12)-7 = 0
(-1/3*2*(x-12))/2+x/2+(-7*2)/2 = 0
x-1/3*2*(x-12)-7*2 = 0
1/3*x-14+8 = 0
1/3*x-6 = 0
(1/3*x-6)/2 = 0
(1/3*x-6)/2 = 0 // * 2
1/3*x-6 = 0
1/3*x-6 = 0 // + 6
1/3*x = 6 // : 1/3
x = 6/1/3
x = 18
Answer: X=2 and y=3
Step-by-step explanation: 2x2=4 and 3x3=9 and 9+4=13
U= uniforms
598+ 24.25u= 1762
24.25u= 1762- 598
24.25u= 1164
U= 1164/24.25
U= 48
The school purchased 48 uniforms.
Hope this helps!
Answer:
Step-by-step explanation:
Hello!
The study variable is:
X: number of customers that recognize a new product out of 120.
There are two possible recordable outcomes for this variable, the customer can either "recognize the new product" or " don't recognize the new product". The number of trials is fixed, assuming that each customer is independent of the others and the probability of success is the same for all customers, p= 0.6, then we can say this variable has a binomial distribution.
The sample proportion obtained is:
p'= 54/120= 0.45
Considering that the sample size is large enough (n≥30) you can apply the Central Limit Theorem and approximate the distribution of the sample proportion to normal: p' ≈ N(p;
)
The other conditions for this approximation are also met: (n*p)≥5 and (n*q)≥5
The probability of getting the calculated sample proportion, or lower is:
P(X≤0.45)= P(Z≤
)= P(Z≤-3.35)= 0.000
This type of problem is for the sample proportion.
I hope this helps!
3 m/h=0.05m/m
.05•5=0.25 m/h I believe?