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Sphinxa [80]
3 years ago
14

Find x if 5x+19=2x+64

Mathematics
2 answers:
tiny-mole [99]3 years ago
7 0

Answer:

5x+19=2x+64

3x+I9=64

3x=45

I5

ZanzabumX [31]3 years ago
3 0

Answer:

x=15

Step-by-step explanation:

5x+19=2x+64

5x-2x=64-19

3x=45

x=15

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1/2×-7=1/3(×-12) solve​
alexgriva [62]

Answer:

X=18

Step-by-step explanation:

(1/2)*x-7 = (1/3)*(x-12) // - (1/3)*(x-12)

(1/2)*x-((1/3)*(x-12))-7 = 0

(-1/3)*(x-12)+(1/2)*x-7 = 0

x/2-1/3*(x-12)-7 = 0

(-1/3*2*(x-12))/2+x/2+(-7*2)/2 = 0

x-1/3*2*(x-12)-7*2 = 0

1/3*x-14+8 = 0

1/3*x-6 = 0

(1/3*x-6)/2 = 0

(1/3*x-6)/2 = 0 // * 2

1/3*x-6 = 0

1/3*x-6 = 0 // + 6

1/3*x = 6 // : 1/3

x = 6/1/3

x = 18

8 0
3 years ago
Whats the answer for 2x+3y=-13 <br><br> I would appreciate all of the work please and thank you
Artemon [7]

Answer: X=2 and y=3

Step-by-step explanation: 2x2=4 and 3x3=9 and 9+4=13

8 0
3 years ago
Read 2 more answers
The school purchased baseball equipment and uniforms for a total cost of 1762.00. The equipment costs 598 and the uniforms were
Norma-Jean [14]
U= uniforms


598+ 24.25u= 1762

24.25u= 1762- 598

24.25u= 1164

U= 1164/24.25

U= 48

The school purchased 48 uniforms.

Hope this helps!
3 0
3 years ago
After an extensive advertising campaign, the manager of a company expects the proportion of potential customers that recognize a
lina2011 [118]

Answer:

Step-by-step explanation:

Hello!

The study variable is:

X: number of customers that recognize a new product out of 120.

There are two possible recordable outcomes for this variable, the customer can either "recognize the new product" or " don't recognize the new product". The number of trials is fixed, assuming that each customer is independent of the others and the probability of success is the same for all customers, p= 0.6, then we can say this variable has a binomial distribution.

The sample proportion obtained is:

p'= 54/120= 0.45

Considering that the sample size is large enough (n≥30) you can apply the Central Limit Theorem and approximate the distribution of the sample proportion to normal: p' ≈ N(p;\sqrt{\frac{p(1-p)}{n} })

The other conditions for this approximation are also met: (n*p)≥5 and (n*q)≥5

The probability of getting the calculated sample proportion, or lower is:

P(X≤0.45)= P(Z≤\frac{0.45-0.6}{\sqrt{\frac{0.6*0.4}{120} } })= P(Z≤-3.35)= 0.000

This type of problem is for the sample proportion.

I hope this helps!

5 0
3 years ago
My friend sets out walking at a speed of 3 miles per hour. I set out behind her 5 minutes later at 4 miles per hour.
MissTica
3 m/h=0.05m/m
.05•5=0.25 m/h I believe?
7 0
3 years ago
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