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3 years ago

A mapping statement is a way of describing a _____ of a figure.

1 answer:

3 0

A mapping system is a way of describing a C. Preimage of a figure. Mapping statements are known to define the range of data sources thus showing all the data. While on the other hand, preimage (in Mathematics) meaning is that set of all the elements of the domain that maps to the members of S.

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I will give brain whoever gives the best answer

miss Akunina [59]

Answer:

1. 5

2. 16.2

3. 1/8

4. 28.2

6 0

2 years ago

Linda and Carrie made a trip from their hometown to a city about 200 miles away to attend a friend's wedding. The following char

marissa [1.9K]

The correct answer is C) 58/73.

We first add up the amount of time spent driving:
3 + 1 1/2 + 20 minutes

Changing 20 minutes to a fraction of an hour, 20/60 = 1/3:
3 + 1 1/2 + 1/3

Using the LCD (6),
3 + 1 3/6 + 2/6 = 4 5/6 hrs driving.

Now we find the total time of the trip:
3 + 15 min + 1 1/2 + 1 + 20 min
= 3 + 15/60 + 1 1/2 + 1 + 20/60
= 3 + 1/4 + 1 1/2 + 1 + 1/3

The LCD for this is 12:
3 + 3/12 + 1 6/12 + 1 + 4/12 = 5 13/12 = 6 1/12

We find the ratio of driving to total time, which is (4 5/6)/(6 1/12)
= 4 5/6 ÷ 6 1/12

Converting the mixed numbers to improper fractions,

29/6 ÷ 73/12 = 29/6 × 12/73 = 348/438 = 174/219 = 58/73

6 0

3 years ago

What is the answer? Please slice and let me know ASAP<br> 4x - 3 ≤ -5

Mice21 [21]

4x - 3 ≤ -5 =

X ≤ -1/2

Explaining

4x ≤ -5 + 3

4x ≤ -2

X ≤ -1/2

3 0

3 years ago

Which statement represents the number line shown?

Arada [10]

Answer:

Step-by-step explanation:

open circle means no underline and it is past the 6 so it is B

7 0

3 years ago

Read 2 more answers

The formula Upper A equals 23.1 e Superscript 0.0152 tA=23.1e0.0152t models the population of a US state, A, in millions, t ye

Wewaii [24]

Answer:

a) $A(t=0)= 23.1 e^{0.0152(0)}=23.1e^0 =23.1$

b) $t = \frac{ln(\frac{28.3}{23.1})}{0.0152}=13.357 years$

So for this case the answer would be 13.347 years, the population will be 28.3 million and ye year would be 2000+13.347 and that would be approximately in 2014

Step-by-step explanation:

For this case we assume the following model:

$A(t)= 23.1 e^{0.0152 t}$

Where t is the number of years after 2000/

Part a

For this case we want the population for 2000 and on this case the value of t=0 since we have 0 years after 2000. If we rpelace into the model we got:

$A(t=0)= 23.1 e^{0.0152(0)}=23.1e^0 =23.1$

So then the initial population at year 2000 is 23.1 million of people.

Part b

For this case we want to find the time t whn the population is 28.3 million.

So we need to solve this equation:

$28.3= 23.1 e^{0.0152(t)}$

We can divide both sides by 23.1 and we got:

$\frac{28.3}{23.1}= e^{0.0152t}$

Now we can apply natural log on both sides and we got:

$ln(\frac{28.3}{23.1})= 0.0152 t$

And then for t we got:

$t = \frac{ln(\frac{28.3}{23.1})}{0.0152}=13.357 years$

So for this case the answer would be 13.347 years, the population will be 28.3 million and ye year would be 2000+13.347 and that would be approximately in 2014

3 0

3 years ago