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Burka [1]
3 years ago
10

What's the property of x ( x - 5y ) + 2y ( X - 5y)

Mathematics
1 answer:
Rasek [7]3 years ago
8 0

Associative property

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Expand (2x-5y)⁷ and find fourth form​
elena55 [62]

Step-by-step explanation:

By binomial theorem,

T(r+1) = nCr * a^(r+1) * b^r

Term 4 = 7C3 * (2x)^4 * (-5y)^3 = 35 * (16x^4) * (-125y^3) = -70000x^4y^3.

3 0
3 years ago
Point P is at the origin. Then Point P is moved 4 units to the right and 5 units up.
taurus [48]

Answer:

Step-by-step explanation:

The origin (x,y) is (0,0)

If its moved four units right you must add 4 to the x coordinate giving you (4,0)

Then it is moved up by 5, so you must add 5 to the y coordinate giving you

(4,5)

8 0
3 years ago
Read 2 more answers
So I have these two assignments and their due in today and 12:00 so if anybody can please give me the answers real quick it woul
LUCKY_DIMON [66]

Answer:

77°, 103°

Step-by-step explanation:

x=103°

  • z=x=103°
  • y=180°-x=180°-103°=77°

-----------

∠5= 42°

∠3= 180°-42°=138°

4 0
3 years ago
One sprinter has a stride of 120cm, another 75cm. How many steps do they each take if they run a 100m race?
Olenka [21]

Answer:

1m = 100 cm

First sprinter stride is 120 cm. Steps he will take

= 100/1.2 = 83 1/3 steps

Second sprinter takes a stride of 75 cm

= 100/0.75 = 133 1/3 steps

3 0
3 years ago
Each letter of the word "supercalifragilisticexpialidocious" is placed into a bag and drawn at 3 times, replacing the letter aft
Makovka662 [10]

Answer:

P(X ≥ 1) = 0.50

Step-by-step explanation:

Given that:

The word "supercalifragilisticexpialidocious" has 34 letters in which 'i' appears 7 times in the word.

Then; the probability of success = 7/34 = 0.20588

Using Binomial distribution to determine the probability; we have:

P(X = x)  = ^nC_x  \ \beta^x   \  (1 - \beta)^{n-x}

where;

x = 0,1,2,...n    and    0  <  β   <   1

and x represents the  number of successes.

However; since the letter is drawn thrice; the probability that the letter "i" is drawn at least once can be computed as:

P(X ≥ 1) = 1 - P(X< 1)

P(X ≥ 1) = 1 - P(X =0)

P(X \ge 1) =  1 - \bigg [ {^3C__0} (0.21)^0 (1-0.21)^{3-0} \bigg]

P(X \ge 1) =  1 - \bigg [ 1 \times 1 (0.79)^{3} \bigg]

P(X ≥ 1) = 1 - 0.50

P(X ≥ 1) = 0.50

4 0
3 years ago
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