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stich3 [128]
3 years ago
9

5 g of margarine contains 3.6 g

Mathematics
1 answer:
Komok [63]3 years ago
8 0

Answer:

59.04g of fat

Step-by-step explanation:

I) Figure out how much grams of fat is in 1g of margarine:

3.6 ÷ 5 = 0.72

II) Next, we can figure out how much fat is in 82 g of margarine:

0.72 × 82 = 59.04

One shot formula:

(3.6g ÷ 5g) × 82g = 59.04g

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Answer:

D = L/k

Step-by-step explanation:

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dA/(L - Ak) = dt

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∫-kdA/-k(L - Ak) = ∫dt

1/k∫-kdA/(L - Ak) = ∫dt

1/k㏑(L - Ak) = t + C

㏑(L - Ak) = kt + kC

㏑(L - Ak) = kt + C'      (C' = kC)

taking exponents of both sides, we have

L - Ak = e^{kt + C'} \\L - Ak = e^{kt}e^{C'}\\L - Ak = C"e^{kt}      (C" = e^{C'} )\\Ak = L - C"e^{kt}\\A = \frac{L}{k}  - \frac{C"}{k} e^{kt}

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So, D = R - A =

D = \frac{L}{k} - \frac{L}{k}  - \frac{L}{k} e^{kt}\\D = \frac{L}{k} e^{kt}

when t = 0(at initial time), the initial value of D =

D = \frac{L}{k} e^{kt}\\D = \frac{L}{k} e^{k0}\\D = \frac{L}{k} e^{0}\\D = \frac{L}{k}

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3 years ago
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