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3 years ago

11

Use this to find the equation of the tangent line to the curve y=5−3x3 at the point (3,−76) and write your answer in the form: y

=mx+b, where m is the slope and b is the y-intercept.

1 answer:

stiv31 [10]3 years ago

5 0

F(x)=5-3x³
f'(x)=-9x²
f'(3)=-81

y+76= -81(x-3)
y+76=-81x+243
y=-81x+167

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