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3 years ago

What value of durbin–watson statistic indicates no autocorrelation is present?

Mathematics

1 answer:

antoniya [11.8K]3 years ago

6 0

Answer:

Step-by-step explanation:

when the value is below 2

a situation in which no identifiable relationship exists between the values of the error term.

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Winton wants to find the volume of a cube. He uses the formula for volume of a cube V = s to the power of 3 where s is the lengt

VARVARA [1.3K]

Answer:

Answer: 0.125 cm^3

8 0

3 years ago

Given f(x) = 3x- 1 and 9(x) = 2x-3, for which value of

Montano1993 [528]

Answer:

x = 4

Step-by-step explanation:

$f(x)=3x-1\\g(x)=2x-3$

substitute x = 2 into f(x):

$f(2)=(3 \times2)-1=5$

equate g(x) with found value for f(2) and solve for x:

$g(x)=f(2)\\2x-3=5\\2x=8\\x=4$

5 0

2 years ago

You have some candies in your pocket. A friend gives you five more candies. When you count all your candies you have 14

defon

Answer:

9 candies

Step-by-step explanation:

You are required to find the number of candies in your pocket

Let

x = number of candies in your pocket

A friend gives you five more candies.

Total candies = 14

This can be represented by the equation:

Total candies = candies in your pocket + candies your friend gave you

14 = x + 5

14 - 5 = x

9 = x

x = 9 candies

x = number of candies in your pocket = 9

7 0

3 years ago

1. Determine the relationship between the two triangles and whether or not they can be proven to be congruent.

Sedaia [141]

Answer:

The two triangles are related by SAS, so the triangles are congruent.

Step-by-step explanation:

We can see that both of them have 2 similar sides, and 1 similar angle. This goes underneath the rule SAS, which makes the triangle congruent

-Chetan K

7 0

2 years ago

Length of a rectangle is 5 cm longer than the width. Four squares are constructed outside the rectangle such that each of the sq

Arte-miy333 [17]

Answer:

The perimeter of rectangle is $18\ cm$

Step-by-step explanation:

Let

x------> the length of rectangle

y----> the width of rectangle

we know that

The area of the constructed figure is equal to

$A=xy+2x^{2} +2y^{2}\\A=120\ cm^{2}$

$120=xy+2x^{2} +2y^{2}$ -----> equation A

$x=y+5$ -----> equation B

substitute equation B in equation A

$120=y(y+5)+2(y+5)^{2} +2y^{2}\\120=y^{2}+5y+2(y^{2}+10y+25)+2y^{2}\\120=y^{2}+5y+2y^{2}+20y+50+2y^{2}\\5y^{2}+25y+50-120=0\\5y^{2}+25y-70=0$

using a graphing calculator to resolve the quadratic equation

the solution is

$y=2\ cm$

Find the value of x

$x=2+5=7\ cm$

Find the perimeter of rectangle

The perimeter of rectangle is equal to

$P=2(x+y)\\P=2(7+2)=18\ cm$

3 0

4 years ago