What is 8.3x10^(-1) converted from standard form to ordinary numbers

Min wants to make 100 name tags with ribbons attached to them. Each name tag requires 5 centimeters of ribbon . She has 3.25 met

ivanzaharov [21]

Min needs exactly 1.75 meters of ribbon to make all 100 name tags.

5 0

3 years ago

There are 6 black scarves, 2 red scarves, and 2 white scarves in a drawer. In the dark, Angela pulls a scarf out of the drawer.

Elenna [48]

There is a 20 percent chance Angela will pull a red scarf, 60 percent chance she will pull a black scarf and 20 percent chance she will pull a white scarf. So if she pulls a red scarf then there will be a 18 percent chance she will pull a white scarf after.
I Hope this helps!

6 0

3 years ago

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Y varies directly with x it has a constant rate of change of 6. When the value of y is 11, then the value of x could be?

makvit [3.9K]

Answer: $\frac{11}{6}$

Explanation:

y varies directly with x means: $\frac{y}{x} = k$ ; where k is the rate

$\frac{y}{x} = k$
$\frac{11}{x} = 6$
$(x)\frac{11}{x} = 6(x)$
11 = 6x
$\frac{11}{6} =\frac{6x}{6}$
$\frac{11}{6} = x$

8 0

3 years ago

A company that produces fine crystal knows from experience that 13% of its goblets have cosmetic flaws and must be classified as

Kisachek [45]

Answer:

(a) The probability that only one goblet is a second among six randomly selected goblets is 0.3888.

(b) The probability that at least two goblet is a second among six randomly selected goblets is 0.1776.

(c) The probability that at most five must be selected to find four that are not seconds is 0.9453.

Step-by-step explanation:

Let X = number of seconds in the batch.

The probability of the random variable X is, p = 0.31.

The random variable X follows a Binomial distribution with parameters n and p.

The probability mass function of X is:

$P(X=x)={n\choose x}p^{x}(1-p)^{n-x};\ x=0,1,2,3...$

(a)

Compute the probability that only one goblet is a second among six randomly selected goblets as follows:

$P(X=1)={6\choose 1}0.13^{1}(1-0.13)^{6-1}\\=6\times 0.13\times 0.4984\\=0.3888$

Thus, the probability that only one goblet is a second among six randomly selected goblets is 0.3888.

(b)

Compute the probability that at least two goblet is a second among six randomly selected goblets as follows:

P (X ≥ 2) = 1 - P (X < 2)

$=1-{6\choose 0}0.13^{0}(1-0.13)^{6-0}-{6\choose 1}0.13^{1}(1-0.13)^{6-1}\\=1-0.4336+0.3888\\=0.1776$

Thus, the probability that at least two goblet is a second among six randomly selected goblets is 0.1776.

(c)

If goblets are examined one by one then to find four that are not seconds we need to select either 4 goblets that are not seconds or 5 goblets including only 1 second.

P (4 not seconds) = P (X = 0; n = 4) + P (X = 1; n = 5)

$={4\choose 0}0.13^{0}(1-0.13)^{4-0}+{5\choose 1}0.13^{1}(1-0.13)^{5-1}\\=0.5729+0.3724\\=0.9453$

Thus, the probability that at most five must be selected to find four that are not seconds is 0.9453.

8 0

3 years ago

If the rectangle ABCD rotated 90 degrees clockwise, which coordinate

pashok25 [27]

Answer:

The answer will be A) A'(4,3)

Step-by-step explanation:

90 degrees will send the rectangle to Quadrant 1, the rectangle itself has also been rotated so by rotating the rectangle 90 degrees and putting it in place for quadrant 1, it should give you the answer.

(You can also rotate the image)

3 0

3 years ago

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