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3 years ago

9

2-2x2-(39 divided by 1)+2+9

1 answer:

artcher [175]3 years ago

6 0

-30 is the answer for your question

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Sorry for the bad picture quality, lol trust me I’m not android user... bUt I really am struggling! Help!-

Klio2033 [76]

Answer:

a to u

Step-by-step explanation:

3 0

3 years ago

What set of reflections would carry parallelogram ABCD onto itself?

My name is Ann [436]

"y-axis, x-axis, y-axis, x-axis" is the set of reflections among the following choices given in the question that <span>would carry parallelogram ABCD onto itself. The correct option among all the options that are given in the question is the third option or the penultimate option. I hope that this is the answer that has helped you.</span>

5 0

3 years ago

Read 2 more answers

Can anyone help me find the coordinates (?,?) given that the shape is a parallelogram? (15 points)

xxTIMURxx [149]

The missing coordinates of the parallelogram is (m + h, n).

Solution:

Diagonals of the parallelogram bisect each other.

Solve using mid-point formula:

$$\text{Midpoint} =\left( \frac{x_1+x_2}{2}, \frac{y_1+y_2}{2}\right )$

Here $x_1=m, y_1=n, x_2=h, y_2=0$

$$=\left( \frac{m+h}{2}, \frac{n+0}{2}\right )$

$$\text{Midpoint} =\left( \frac{m+h}{2}, \frac{n}{2}\right )$

<u>To find the missing coordinate:</u>

Let the missing coordinates by x and y.

Here $x_1=0, y_1=0, x_2=x, y_2=y$

$$\text{Midpoint}=\left( \frac{0+x}{2}, \frac{0+y}{2}\right )$

$$\left( \frac{m+h}{2}, \frac{n}{2}\right )=\left( \frac{0+x}{2}, \frac{0+y}{2}\right )$

$$\left( \frac{m+h}{2}, \frac{n}{2}\right )=\left( \frac{x}{2}, \frac{y}{2}\right )$

Now equate the x-coordinate.

$$ \frac{m+h}{2}=\frac{x}{2}$

Multiply by 2 on both sides of the equation, we get

m + h = x

x = m + h

Now equate the y-coordinate.

$$\frac{n}{2} = \frac{y}{2}$

Multiply by 2 on both sides of the equation, we get

n = y

y = n

Hence the missing coordinates of the parallelogram is (m + h, n).

5 0

3 years ago

Question 6 of 10

Vinil7 [7]

62 triangle a and 59 triangle b

6 0

3 years ago

Hello I need help<br> Find the missing side lengths, leave your answers as radicals in simplest form

Jet001 [13]

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$y = \frac{1}{2} \times \frac{8 \sqrt{3} }{3} \\$

$y = \frac{4 \sqrt{3} }{3} \\$

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$x = \frac{ \sqrt{3} }{2} \times \frac{8 \sqrt{3} }{3} \\$

$x = \frac{8 \times { \sqrt{3} }^{2} }{2 \times 3} \\$

$x = \frac{8 \times 3}{2 \times 3} \\$

$x = \frac{8}{2} \\$

$x = 4$

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4 0

3 years ago