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mrs_skeptik [129]
3 years ago
7

NEED HELP PLEASE!!!! 15 POINTS!

Mathematics
1 answer:
Tanya [424]3 years ago
5 0

Answer:

69

Step-by-step explanation:

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I am sus lol so here is some points​
Masja [62]

Hello.

Have a beautiful and joyful day ahead

Thanks for points..

3 0
3 years ago
What is the value of 1/2 of 2/3 of 3/4 of 4/5 of 5/6 of 6/7 of 7/8 of 8/9 of 9/10 of 1000?
Alenkasestr [34]

Answer:

it's 100

Step-by-step explanation:

9/10 of 1000 is 900, 8/9 of 900 is 800, 7/8 of 800 is 700, 6/7 of 700 is 600, 5/6 of 600 is 500, 4/5 of 500 is 400, 3/4 of 400 is 300, 2/3 of 300 is 200, and 1/2 of 200 is 100 which makes 100 the value of 1/2 of 2/3 of 3/4 of 4/5 of 5/6 of 6/7 of 7/8 of 8/9 of 9/10 of 1000? I hope this makes sense.

5 0
3 years ago
Find the area of the rhombus
MAXImum [283]
<h3> Solution :-</h3>

Area of rhombus :-

\bf  \star \:  \:  \boxed{ \bf  \dfrac{d_{1}d_{2}}{2} }

\sf \longrightarrow d_{1} = 4 \sqrt{3}  + 4 \sqrt{3} = 8 \sqrt{3}

\sf \longrightarrow d_{2}  = 4 + 4 = 8

Area of rhombus :-

:  \implies \sf  \dfrac{8 \sqrt{3} \times 8 }{2}

:   \implies \sf  8 \sqrt{3}  \times 4

:  \implies \bf 32 \sqrt{3}  \:  {m}^{2}

6 0
2 years ago
Use the discriminant to find the number and type of solution for x^2+6x=-9​
likoan [24]

Answer:

D = 0; one real root

Step-by-step explanation:

Discriminant Formula:

\displaystyle \large{D =  {b}^{2}  - 4ac}

First, arrange the expression or equation in ax^2+bx+c = 0.

\displaystyle \large{ {x}^{2}  + 6x =  - 9}

Add both sides by 9.

\displaystyle \large{ {x}^{2}  + 6x + 9 =  - 9 + 9} \\  \displaystyle \large{ {x}^{2}  + 6x + 9 =  0}

Compare the coefficients so we can substitute in the formula.

\displaystyle \large{a {x}^{2}  + bx + c =  {x}^{2}  + 6x + 9 }

  • a = 1
  • b = 6
  • c = 9

Substitute a = 1, b = 6 and c = 9 in the formula.

\displaystyle \large{D =  {6}^{2}  - 4(1)(9)} \\  \displaystyle \large{D =  36 - 36} \\  \displaystyle \large{D =  0}

Since D = 0, the type of solution is one real root.

6 0
2 years ago
R2+2r-33=0 solve by completing the square
-BARSIC- [3]
R^2+2r-33=0  move constant to other side by adding 33 to both sides

r^2+2r=33   halve the linear coefficient, square it and add to both sides, in this case it is just one

r^2+2r+1=34  now the left side is a perfect square...

(r+1)^2=34  take the square root of both sides...

r+1=34^(1/2)  subtract 1 from both sides

r=-1+34^(1/2) and -1-34^(1/2)
8 0
3 years ago
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