Answer:
See solutions for detail.
Step-by-step explanation:
a.
is the instantaneous rate of change of volume given with respect to time, t.
The volume's rate of change is written as a function of time.
-
is the rate of change in the height of water in the tank with respect to time, t.
b.
is the only constant. Water flows into the constant at a constant rate, say
per minute.
c.
is positive. Volume water in the take is increasing from time to time.
-The volume at time t=1 is greater than the volume at t=0, hence, it's a positive rate of change.
d.
is a positive rate. The initial height of water in the tank is zero.
-The final height at time t is 0.25h. The height is increasing with time.
Hence, it is positive.
Answer:
![\boxed{20(r + 3t)}](https://tex.z-dn.net/?f=%5Cboxed%7B20%28r%20%2B%203t%29%7D)
Step-by-step explanation:
![20r + 60t](https://tex.z-dn.net/?f=20r%20%2B%2060t)
Factor out 20 from the expression.
![20(r) + 20(3t)](https://tex.z-dn.net/?f=20%28r%29%20%2B%2020%283t%29)
Take 20 as common.
![20(r + 3t)](https://tex.z-dn.net/?f=20%28r%20%2B%203t%29)
Answer:
The answer is x = 20
Step-by-step explanation:
If you set both equations equal to each other and solve for x, you will get 20.
3x+32 = 5x-8 add 8 to both sides
3x+40 = 5x subtract 3x from both sides
40 = 2x divide by 2 on both sides
20 = x
Answer:
ill say the 8 pack
Step-by-step explanation:
Answer: 0.2643
Step-by-step explanation:
Let p be the population proportion and
be the sample proportion .
As per given question , we have
![p=0.14\\\\ \hat{p}=0.13\\\\ n=478](https://tex.z-dn.net/?f=p%3D0.14%5C%5C%5C%5C%20%5Chat%7Bp%7D%3D0.13%5C%5C%5C%5C%20n%3D478)
z-score : ![\dfrac{\hat{p}-p}{\sqrt{\dfrac{p(1-p)}{n}}}](https://tex.z-dn.net/?f=%5Cdfrac%7B%5Chat%7Bp%7D-p%7D%7B%5Csqrt%7B%5Cdfrac%7Bp%281-p%29%7D%7Bn%7D%7D%7D)
![z=\dfrac{0.13-0.14}{\sqrt{\dfrac{0.14(1-0.14)}{478}}}\\\\=-0.630087269176\approx-0.63](https://tex.z-dn.net/?f=z%3D%5Cdfrac%7B0.13-0.14%7D%7B%5Csqrt%7B%5Cdfrac%7B0.14%281-0.14%29%7D%7B478%7D%7D%7D%5C%5C%5C%5C%3D-0.630087269176%5Capprox-0.63)
The required probability ( using z-table ):-
![P(z](https://tex.z-dn.net/?f=P%28z%3C-0.63%29%3D1-P%28z%3C0.63%29%5C%5C%5C%5C%3D1-%200.7356527%3D0.2643473%5Capprox0.2643)
Hence, the probability that the proportion of books checked out in a sample of 478 books would be less than 13% = 0.2643