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LUCKY_DIMON [66]
3 years ago
8

The choir is planning a trip to the water park. The cost to use a school bus is $350. Complete the table at the right then graph

your result. Is this a proportional relationship?

Mathematics
2 answers:
faust18 [17]3 years ago
8 0
350÷10=35
350÷15=23 1/3 or 23.34
350÷20=17.50
350÷35=10
nasty-shy [4]3 years ago
6 0

Answer:

10 students: Bus cost per student is $35

15 students: Bus cost per student is $23.24.

20 students: Bus cost per student is $17.5

35 students: Bus cost per student is $10

Step-by-step explanation:

We are given the following information in the question:

Cost to use school bus = $350

Bus cost per student =

\displaystyle\frac{\text{Total Cost}}{\text{Number of students}}\

Number of students = 10

Bust cost per student =

\displaystyle\frac{350}{10} = \$35

When there are 10 students the bus cost per student is $35.

Number of students = 15

Bust cost per student =

\displaystyle\frac{350}{15} = \$23.34

When there are 15 students the bus cost per student is $23.34.

Number of students = 20

Bust cost per student =

\displaystyle\frac{350}{20} = \$17.5

When there are 20 students the bus cost per student is $17.5.

Number of students = 35

Bust cost per student =

\displaystyle\frac{350}{35} = \$10

When there are 35 students the bus cost per student is $10.

The attached image shows a plot for the given situation.

No, the given relationship in not proportional. If two quantities are proportional, then they have a constant ratio, which cannot be said for the given scenario.

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USE THE ATTACHED IMAGE BELOW TO HELP DO MY HOMEWORK PLEASE<br> !!!!
BartSMP [9]

Part A

Sue

A = P*(1+r/n)^(n*t) is the compound interest formula

A = 2300*(1+0.024/1)^(1*3)

A = 2469.6061952

A = 2469.61

A - P = 2469.61-2300 = 169.61

<h3>Sue gets 169.61 pounds in interest</h3>

-----------

Bill

A = P*(1+r/n)^(n*t)

A = 1800*(1+0.034/1)^(1*3)

A = 1989.9131472

A = 1989.91

A-P = 1989.91-1800 = 189.91

<h3>Bill earns 189.91 pounds in interest</h3>

Bill has earned more in interest.

=====================================================

Part B

By year 2, Bill has 1924.48 pounds in his account based on the work shown below

A = P*(1+r/n)^(n*t)

A = 1800*(1+0.034/1)^(1*2)

A = 1924.4808

A = 1924.48

This amount is the new deposit, so to speak, when we change the interest rate. Now r = 0.034 changes to r = 0.04. We only go for one year so t = 1

A = P*(1+r/n)^(n*t)

A = 1924.48*(1+0.04/1)^(1*1)

A = 2001.4592

A = 2001.46

Bill has 2001.46 pounds in his account after 3 years if the interest rate for the 1234 account changes to 4% in the third year.

Now subtract off the original amount Bill deposited to get

2001.46-1800 = 201.46

For this scenario, Bill earns 201.46 pounds in interest.

Therefore, Bill has earned the most interest for both cases of the interest rate staying at 3.4% or changing to 4% for that third year.

<h3>Answer: Bill</h3>
8 0
3 years ago
A Cell Phone company sells cellular phones and airtime in a State. At a recent meeting, the marketing manager states that the av
GarryVolchara [31]

Answer:

The null hypothesis is rejected.

There is enough evidence to support the claim that the average age of the customers differs from 40 years.

The sample does not support the manager claim (the average age seems to differ from 40 years).

Step-by-step explanation:

This is a hypothesis test for the population mean.

The manager claims that the average age of customers is 40 years. As this is an equality, we will test if the average age differs from 40. If the null hypothesis failed to be rejected, the claim of the manager is right.

Then, the claim is that the average age of the customers differs from 40 years.

Then, the null and alternative hypothesis are:

H_0: \mu=40\\\\H_a:\mu\neq 40

The significance level is 0.05.

The sample has a size n=50.

The sample mean is M=38.

As the standard deviation of the population is not known, we estimate it with the sample standard deviation, that has a value of s=7.

The estimated standard error of the mean is computed using the formula:

s_M=\dfrac{s}{\sqrt{n}}=\dfrac{7}{\sqrt{50}}=0.99

Then, we can calculate the t-statistic as:

t=\dfrac{M-\mu}{s/\sqrt{n}}=\dfrac{38-40}{0.99}=\dfrac{-2}{0.99}=-2.02

The degrees of freedom for this sample size are:

df=n-1=50-1=49

This test is a two-tailed test, with 49 degrees of freedom and t=-2.02, so the P-value for this test is calculated as (using a t-table):

P-value=2\cdot P(t

As the P-value (0.049) is smaller than the significance level (0.05), the effect is  significant.

The null hypothesis is rejected.

There is enough evidence to support the claim that the average age of the customers differs from 40 years.

3 0
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