Ask question

Ask question

All categories

3 years ago

6

The area of a rectangular fountain is x2 + 9x + 20 square feet. A 5-foot walkway is built around the fountain. Find the dimensio

ns of the outside border of the walkway. The dimensions of the outside border of the walkway are _ feet and _ feet (fill in the _ s)

1 answer:

Leviafan [203]3 years ago

6 0

Answer:

So, the dimensions of the outside border of the walkway are (x + 14) feet (x + 15) feet.

You might be interested in

How much will have to deposit into an account that pays 5.25% simple interest today, in order to earn $345.45 interest in seven

Ann [662]

To earn $345.45 simple interest in 7 years, you have to invest $940.

<u>Step-by-step explanation:</u>

Step 1:

Given details are Simple Interest Rate (R) = 5.25%, Simple Interest (SI) = $345.45, Time (T) = 7 years

Step 2:

Use the above details to find principal using the formula for Simple Interest (SI) = PRT/100

⇒ 345.45 = (P × 5.25 × 7)/100

⇒ 34545 = 36.75 P

⇒ P = $940

3 0

3 years ago

Is 4(4a+20b) equivalent to 16a+24b

8090 [49]

No.

When you are distributing, you are multiplying to each monomial

4(4a) = 16a

4(20b) = 80b

16a + 80b is your actual answer

hope this helps

7 0

4 years ago

Please help.<br> Is algebra.<br> PLEASE HELP NO LINKS OR FILES.<br> I don't want links.

inysia [295]

It would be B! :) have a good day

3 0

3 years ago

Fifteen students were divided into two classrooms in a ratio of 1:2.

IgorC [24]

The answer: In Classroom 1, there are 5 students while in Classroom 2, there are 10 students.

Explanation:
x + 2x = 3x
3x = 15
x = 5, Classroom 1 = 5, Classroom 2 = 5 x 2 = 10

I hope that this helps! :)

3 0

2 years ago

Verify that the following function is a probability mass function, and determine the requested probabilities. f left-parenthesis

Licemer1 [7]

Answer:

$f(x) = \frac{27}{13} (\frac{1}{3})^x , x=1,2,3$

1) $f(x_i) \geq 0, \forall x_i$

2) $sum_{i=1}^n P(X_i) =1$

We can find the individual probabilities and we got:

$f(1)= \frac{27}{13} (\frac{1}{3})^1 =0.6923$

$f(2)= \frac{27}{13} (\frac{1}{3})^2 =0.2307$

$f(3)= \frac{27}{13} (\frac{1}{3})^3 =0.0770$

And the sum of the 3 values 0.6923+0.2307+0.0770= 1 so then we satisfy all the conditions and we can conclude that f(x) is a probability distribution.

$P(X \leq 1) = P(X=1) =0.6923$

$P(X>1) = P(X=2) +P(X=3) = 0.2307+0.0770=0.3077$

$P(2$

Step-by-step explanation:

For this case we have the following density function:

$f(x) = \frac{27}{13} (\frac{1}{3})^x , x=1,2,3$

In order to satisfty that this function is a probability mass function we need to check two conditions:

1) $f(x_i) \geq 0, \forall x_i$

2) $sum_{i=1}^n P(X_i) =1$

We can find the individual probabilities and we got:

$f(1)= \frac{27}{13} (\frac{1}{3})^1 =0.6923$

$f(2)= \frac{27}{13} (\frac{1}{3})^2 =0.2307$

$f(3)= \frac{27}{13} (\frac{1}{3})^3 =0.0770$

And the sum of the 3 values 0.6923+0.2307+0.0770= 1 so then we satisfy all the conditions and we can conclude that f(x) is a probability distribution.

And if we want to find the following probabilities:

$P(X \leq 1) = P(X=1) =0.6923$

$P(X>1) = P(X=2) +P(X=3) = 0.2307+0.0770=0.3077$

$P(2$

7 0

3 years ago